The answer is Alternating Current
Answer:
16 Newtons
Explanation:
We will use the equation F=ma
First, find the acceleration using the givens.
a=∆v/∆t
a=15-3/3
a=12/3
a=4 m/s^2
Next, plug the acceleration and mass into the equation.
F=ma
F=4kg(4m/s^2)
F=16 Newtons
Answer:
<h2>2 N</h2>
Explanation:
The force engine exert on the car can be found by using the formula
w is the workdone
d is the distance
From the question we have
We have the final answer as
<h3>2 N</h3>
Hope this helps you
Explanation:
here, u = 5m/s,a = 3m/s2, v = 23m/s, t = ?, s = ?
v = u+at
23 = 5 + 3t
t = 23- 5/3 = 18/3 = 6 sec
s= ut + 1/2 at ^2
s = 5 * 6 + 1/2 * 3 * (6)^2
s = 30 + 1/2 * 3 * 36
s = 30 + 18 * 3
s= 30 + 54 = 84 m
here, u = 0, a = x, t = 5min = 300 sec, s= 5.8km = 5800m
s = ut + 1/2 at^2
5800 = 0 * 300 + 1/2 * x * (300)^2
5800 = 1/2 * x * 90000
5800= 45000 x
x = 5800/45000
x = 0.12m/sec^2
here, v = 0, t = 6sec, s = ?, a = - 9.8m/s2
s = UT + 1/2 at ^2
s = 29.4 * 3 + 1/2 * - 9.8 * (3)^2
s= 88.2 - 44.1
s= 44.1 m
s = ut + 1/2 at ^2
s = 0 * 1 + 1*2 * 9.8 * (1)^2
s = 4.9m
hope it helps you
Answer:
2N
Explanation:
Given that a student pulls down with a force of 40 N on a rope that winds around a pulley of radius 5 cm. find the torque?
Solution
Using the formula
Torque = Force × radius
I.e
Torque = F r
Where
F = 40N
r = 5 cm = 5/100 = 0.05m
Substitute all the parameters into the formula
Torque = 40 × 0.05
Torque = 2 N
Therefore, the torque on this scenario is 2 N
