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Igoryamba
2 years ago
7

When sound waves superimpose they can interfere?

Physics
1 answer:
gtnhenbr [62]2 years ago
6 0

Answer:    

Explanation:

When two waves of similar frequency arrive at the same point and superimpose, they alternately constructively and destructively interfere. This alternating is known as a beat because it produces an unpleasant pulsing sound

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What current is used to power the United States power grid?
alexdok [17]
The answer is Alternating Current
3 0
3 years ago
Read 2 more answers
What is the force required to accelerate a 4 kg rock from 3 m/s to 15 m/s in seconds?
Lera25 [3.4K]

Answer:

16 Newtons

Explanation:

We will use the equation F=ma

First, find the acceleration using the givens.

a=∆v/∆t

a=15-3/3

a=12/3

a=4 m/s^2

Next, plug the acceleration and mass into the equation.

F=ma

F=4kg(4m/s^2)

F=16 Newtons

4 0
4 years ago
If a small motor does 520 J of work to move a toy car 260 m, what force does the engine exert on the car?
ohaa [14]

Answer:

<h2>2 N</h2>

Explanation:

The force engine exert on the car can be found by using the formula

f =  \frac{w}{d}  \\

w is the workdone

d is the distance

From the question we have

f =  \frac{520}{260}  = 2 \\

We have the final answer as

<h3>2 N</h3>

Hope this helps you

4 0
3 years ago
1. A car with an initial velocity of 5m/s acceaccelerates uniformly at 3 metre per second square until it reaches a velocity of
alisha [4.7K]

Explanation:

here, u = 5m/s,a = 3m/s2, v = 23m/s, t = ?, s = ?

v = u+at

23 = 5 + 3t

t = 23- 5/3 = 18/3 = 6 sec

s= ut + 1/2 at ^2

s = 5 * 6 + 1/2 * 3 * (6)^2

s = 30 + 1/2 * 3 * 36

s = 30 + 18 * 3

s= 30 + 54 = 84 m

here, u = 0, a = x, t = 5min = 300 sec, s= 5.8km = 5800m

s = ut + 1/2 at^2

5800 = 0 * 300 + 1/2 * x * (300)^2

5800 = 1/2 * x * 90000

5800= 45000 x

x = 5800/45000

x = 0.12m/sec^2

here, v = 0, t = 6sec, s = ?, a = - 9.8m/s2

s = UT + 1/2 at ^2

s = 29.4 * 3 + 1/2 * - 9.8 * (3)^2

s= 88.2 - 44.1

s= 44.1 m

s = ut + 1/2 at ^2

s = 0 * 1 + 1*2 * 9.8 * (1)^2

s = 4.9m

hope it helps you

8 0
3 years ago
A student pulls down with a force of 40 N on a rope that winds around a pulley of radius 5 cm. find the torque?
Anna71 [15]

Answer:

2N

Explanation:

Given that a student pulls down with a force of 40 N on a rope that winds around a pulley of radius 5 cm. find the torque?

Solution

Using the formula

Torque = Force × radius

I.e

Torque = F r

Where

F = 40N

r = 5 cm = 5/100 = 0.05m

Substitute all the parameters into the formula

Torque = 40 × 0.05

Torque = 2 N

Therefore, the torque on this scenario is 2 N

7 0
3 years ago
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