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Savatey [412]
2 years ago
10

If water were a non-polar Molecule

Chemistry
1 answer:
JulijaS [17]2 years ago
8 0

Answer:

Water would not be able to transport nutrients -‐-‐ in plants, or in our bodies -‐-‐ nor to dissolve and transport waste products out of our bodies. ... Cohesiveness, adhesiveness, and surface tension: would decrease because without the +/-‐ polarity, water would not form hydrogen bonds between H20 molecules.

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Find the number of kilograms in 15.40 moles of C5H10O5
OLga [1]
C5H10O5 would weight a total of 2.312 kilograms.
5 0
3 years ago
A gas exerts a pressure of 350.0 torr at 20.0 Celsius. What would be the new pressure in atmospheres if the temperature is raise
IgorC [24]

Answer:

373.88 torr

Explanation:

P1 = 350 torr

T1 = 20°C = (20 + 273.15)K = 293.15K

P2 = ?

T2 = 40°C = (40 + 273.15)K = 313.15K

From pressure law,

Pressure of a given mass of gas is directly proportional to its temperature.

P = KT

K = P / T

P1 / T1 = P2 / T2

Solve for P2

P2 = (P1 * T2) / T1

P2 = (350 * 313.15) / 293.15

P2 = 109602.5 / 293.15

P2 = 373.878 torr

P2 = 373.88 torr

The new pressure of the gas would be 373.88 torr.

5 0
3 years ago
Read 2 more answers
What is the molar mass of 3.45 moles of NO2
marissa [1.9K]

I Believe it would be 46.005500

hoped this helped let me know if I'm wrong

4 0
3 years ago
Read 2 more answers
How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?
shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

                                       = 1.6 mol \times 249.68 g/mol

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

4 0
3 years ago
Which best describes nuclear fission?
rewona [7]

Answer:

C. The splitting apart of atomic nuclei

Explanation:

Nuclear fission is the splitting apart of atomic nuclei.

7 0
2 years ago
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