The awnser is D or the 4th one
Well, first we must remember that
![pK_{a}+pK_{b}=14](https://tex.z-dn.net/?f=pK_%7Ba%7D%2BpK_%7Bb%7D%3D14)
This is because
![K_{a}*K_{b}=10^{-14}](https://tex.z-dn.net/?f=K_%7Ba%7D%2AK_%7Bb%7D%3D10%5E%7B-14%7D)
![-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14](https://tex.z-dn.net/?f=-log%28K_%7Ba%7D%2AK_%7Bb%7D%29%3D-log%2810%5E%7B-14%7D%29%5C%5C-logK_%7Ba%7D%2B-logK_%7Bb%7D%3D-log%2810%5E%7B-14%7D%29%5C%5CpK_%7Ba%7D%2BpK_%7Bb%7D%3D14)
So then
![pK_{b}=14-pK_{a}=14-3.2=1.8](https://tex.z-dn.net/?f=pK_%7Bb%7D%3D14-pK_%7Ba%7D%3D14-3.2%3D1.8)
Answer:
1. 80g
2. 1.188mole
Explanation:
1. We'll begin by obtaining the molar mass of CH4. This is illustrated below:
Molar Mass of CH4 = 12 + (4x1) = 12 + 4 = 16g/mol
Number of mole of CH4 from the question = 5 moles
Mass of CH4 =?
Mass = number of mole x molar Mass
Mass of CH4 = 5 x 16
Mass of CH4 = 80g
2. Mass of O2 from the question = 38g
Molar Mass of O2 = 16x2 = 32g/mol
Number of mole O2 =?
Number of mole = Mass /Molar Mass
Number of mole of O2 = 38/32
Number of mole of O2 = 1.188mole
When there are 14c-lable uracil that are added to the growth medium of cells, the macromolecules that will be labled are RNA. Uracil is a nucleobase that make up the DNA or the RNA. In RNA, uracil binds with other nucleobase (adenine) through hydrogen bonds.