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iogann1982 [59]
2 years ago
14

How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?

Chemistry
1 answer:
Kamila [148]2 years ago
7 0

Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₄H₆O₃: 1 mole
  • C₇H₆O₃: 1 mole
  • C₉H₈O₄: 1 mole
  • C₂H₄O₂: 1 mole

The molar mass of the compounds is:

  • C₄H₆O₃: 102 g/mole
  • C₇H₆O₃: 138 g/mole
  • C₉H₈O₄: 180 g/mole
  • C₂H₄O₂: 60 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₄H₆O₃: 1 mole ×102 g/mole= 102 grams
  • C₇H₆O₃: 1 mole ×138 g/mole= 138 grams
  • C₉H₈O₄: 1 mole ×180 g/mole= 180 grams
  • C₂H₄O₂: 1  mole ×60 g/mole= 60 grams

<h3>Mass of aspirin formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}

<u><em>mass of aspirin= 2.713 grams</em></u>

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

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Explanation:

<em>Structural formula is attached</em>

IUPAC naming rules

1. start numbering the chain from the functional group. In this compound we        start from oxygen side.

2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.

3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.

4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane

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What is the molarity if a solution that contains 289 grams of sugar in a 2 liter solution?? Molar mass of source is 342.2965g/mo
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<u>Answer;</u>

= 0.422 M

<h3><u>Explanation;</u></h3>

Molarity or concentration is the number of moles of a solute in 1 liter of a solution.

Therefore; Molarity = n/V ; where n is the number of moles and V is the volume of the solution in L.

Number of moles = Mass/molar mass

                             = 289 g/342.2965g/mol

                             = 0.844 Moles

Therefore;

Molarity = 0.844 moles/ 2L

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