Molar mass O2 = 31.99 g/mol
Molar mass CO2 = 44.01 g/mol
Moles ratio:
<span>C3H8 + 5 O2 = 3 CO2 + 4 H2O
</span>
5 x 44.01 g O2 ---------------- 3 x 44.01 g CO2
( mass of O2) ------------------ 37.15 g CO2
mass of O2 = 37.15 x 5 x 44.01/ 3 x 44.01
mass of O2 = 8174.8575 / 132.03
mass of O2 = 61.916 g
Therefore:
1 mole O2 ----------------- 31.99 g
moles O2 -------------------- 61.916
moles O2 = 61.916 x 1 / 31.99
moles = 61.916 / 31.99 => 1.935 moles of O2
Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles
Explanation : Given,
Mass of calcium hydroxide = 369 g
Molar mass of calcium hydroxide = 74.093 g/mole
Formula used :

Now put all the given values in this formula, we get the moles of calcium hydroxide.

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles
Answer:
the property that is shared between liquids us called thermometric property your welcome
23. The correct answer would be a (AlPO4 + H2O).
This is an example of a neutralization reaction (an acid and a base react to form water and a salt).
24. a, combination reaction. There are two reactants and one product.