Answer:
Explanation:
Given
length of rope ![L=19\ m](https://tex.z-dn.net/?f=L%3D19%5C%20m)
velocity while running ![v=2\ m/s](https://tex.z-dn.net/?f=v%3D2%5C%20m%2Fs)
when the person jumps off the bank and hang on the rope then we can treat the person as pendulum with Time period T which is given by
![T=2\pi \sqrt{\frac{L}{g}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cfrac%7BL%7D%7Bg%7D%7D)
![T=2\pi \sqrt{\frac{19}{9.8}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cfrac%7B19%7D%7B9.8%7D%7D)
![T=2\pi \times 1.392](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Ctimes%201.392)
![T=8.74\ m/s](https://tex.z-dn.net/?f=T%3D8.74%5C%20m%2Fs)
Greatest Possible distance will be covered when person reaches the other extreme end of assumed pendulum (velocity=zero)
therefore he must hang on for 0.5 T time
![time=0.5\times 8.74=4.37\ s](https://tex.z-dn.net/?f=time%3D0.5%5Ctimes%208.74%3D4.37%5C%20s)
Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 ![in^{2}](https://tex.z-dn.net/?f=in%5E%7B2%7D)
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = ![\frac{F}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7BA%7D)
⇒ P = ![\frac{6.4}{0.4}](https://tex.z-dn.net/?f=%5Cfrac%7B6.4%7D%7B0.4%7D)
⇒ P = 16 ![\frac{lb}{in^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Blb%7D%7Bin%5E%7B2%7D%20%7D)
This is the pressure inside the cylinder.
Let force applied on the brake pad = ![F_{1}](https://tex.z-dn.net/?f=F_%7B1%7D)
Area of the brake pad (
)= 1.7 ![in^{2}](https://tex.z-dn.net/?f=in%5E%7B2%7D)
Thus the pressure on the brake pad (
) = ![\frac{F_{1} }{A_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7BF_%7B1%7D%20%7D%7BA_%7B1%7D%20%7D)
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P = ![P_{1}](https://tex.z-dn.net/?f=P_%7B1%7D)
⇒ 16 = ![\frac{F_{1} }{A_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7BF_%7B1%7D%20%7D%7BA_%7B1%7D%20%7D)
⇒
= 16 × ![A_{1}](https://tex.z-dn.net/?f=A_%7B1%7D)
Put the value of
we get
⇒
= 16 × 1.7
⇒
= 27.2 lb
This the total force applied during braking.
The force applied on one wheel =
=
= 6.8 lb
⇒ The force applied on one wheel during braking.
Answer:
the magnitude of Vpg = 493.711 km/h
Explanation:
given data
speed Vpg = 560 km/h
speed Vwg = 80 km/h
solution
we get here magnitude of the plane velocity w.r.t. ground is
we know that the Vpg = Vpw + Vwg .....................1
writing the component of the velocity that is
Vpw = (0 km/h î - 560 km/h j )
Vwg = (80 cos 45 km/h î + 80 sin 45 km/h j)
adding these
Vpg = (0+80 cos 45 km/h ) î + ( -560 + 80 sin 45 km/h j)i
Vpg = (42.025 ) î (-491.92 km/h)j
now we take magnitude
the magnitude of Vpg = ![\sqrt{(42.025^2+(-491.92)^2)} km/h](https://tex.z-dn.net/?f=%5Csqrt%7B%2842.025%5E2%2B%28-491.92%29%5E2%29%7D%20km%2Fh)
the magnitude of Vpg = 493.711 km/h
The area under the acceleration time graph represents change in velocity
The graph is plotted with acceleration on the vertical axis and time on the horizontal axis. The area under such graph represents change in velocity
Answer:
Examples include cars, buildings, clothing, and tools. Nonmaterial culture refers to the abstract ideas and ways of thinking that make up a culture. Examples of nonmaterial culture include traffic laws, words, and dress codes.