Answer:
Circular motion: find period, find radius, find velocity, find centripetal acceleration 27 V= T a =vºlr=rw
Explanation:
Answer:
Extraneous
Explanation:
Extraneous variables are any variables that you are not intentionally studying in your experiment or test
Answer:
4.96 × 10⁵ Pa
Explanation:
F = mg
![F = (m_{person}+m_{stool})g\\\\F = (4.5 + 89)*9.8\\\\F = 916.3 N](https://tex.z-dn.net/?f=F%20%3D%20%28m_%7Bperson%7D%2Bm_%7Bstool%7D%29g%5C%5C%5C%5CF%20%3D%20%20%284.5%20%2B%2089%29%2A9.8%5C%5C%5C%5CF%20%3D%20916.3%20N)
This force is evenly distributed on the three leg
radius, r = d/2
= 2.8 / 2
= 1.4 cm = 0.014 m
total cross sectional area of the three legs, A = 3*pi*r^2
![= 3\times\pi \times0.014^2\\\\= 1.847\times10^-^3m^2](https://tex.z-dn.net/?f=%3D%203%5Ctimes%5Cpi%20%5Ctimes0.014%5E2%5C%5C%5C%5C%3D%201.847%5Ctimes10%5E-%5E3m%5E2)
Pressure due to weight,
P = Weight/A
![P = / 1.847 × 10⁻³\\P = \frac{ 916.3N}{1.847\times10^-^3} \\\\P= 496032.9Pa](https://tex.z-dn.net/?f=P%20%3D%20%2F%201.847%20%C3%97%2010%E2%81%BB%C2%B3%5C%5CP%20%3D%20%5Cfrac%7B%20916.3N%7D%7B1.847%5Ctimes10%5E-%5E3%7D%20%5C%5C%5C%5CP%3D%20496032.9Pa)
P = 4.96 × 10⁵ Pa
Answer:
I'm pretty sure it's 3.
Explanation:
Because if you look at your options the only that would be relevant to tick marks would be either 4 or 3. And it said in the question that we're looking for the one for the dependent variable. And the dependent variable is on the Y- Axis and the 3 is the tick marks for the y-axis. So your answer is 3.
Answers:
a) ![65.075 kgm/s](https://tex.z-dn.net/?f=65.075%20kgm%2Fs)
b) ![10.526 s](https://tex.z-dn.net/?f=10.526%20s)
c) ![61.82 N](https://tex.z-dn.net/?f=61.82%20N)
Explanation:
<h3>a) Impulse delivered to the ball</h3>
According to the Impulse-Momentum theorem we have the following:
(1)
Where:
is the impulse
is the change in momentum
is the final momentum of the ball with mass
and final velocity (to the right) ![V_{2}=57 m/s](https://tex.z-dn.net/?f=V_%7B2%7D%3D57%20m%2Fs)
is the initial momentum of the ball with initial velocity (to the left) ![V_{1}=-38 m/s](https://tex.z-dn.net/?f=V_%7B1%7D%3D-38%20m%2Fs)
So:
(2)
(3)
(4)
(5)
<h3>b) Time </h3>
This time can be calculated by the following equations, taking into account the ball undergoes a maximum compression of approximately
:
(6)
(7)
Where:
is the acceleration
is the length the ball was compressed
is the time
Finding
from (7):
(8)
(9)
(10)
Substituting (10) in (6):
(11)
Finding
:
(12)
<h3>c) Force applied to the ball by the bat </h3>
According to Newton's second law of motion, the force
is proportional to the variation of momentum
in time
:
(13)
(14)
Finally:
![F=61.82 N](https://tex.z-dn.net/?f=F%3D61.82%20N)