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frosja888 [35]
3 years ago
12

Why does the car stop? Where did the energy go?

Physics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

Because you hit the break?

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Block A is also connected to a horizontally-mounted spring with a spring constant of 281 J/m2. What is the angular frequency (in
Svetradugi [14.3K]

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the formula to be used here is

ω = 2π/T

Where ω is the angular frequency (in rad/s)

T is the period - the time taken for Block A to complete one oscillation and return to it's original position.

To solve for this period T, the formula below should be used

T = 2π√m/k

where m is the mass of the object (Block A) and k is the spring constant (281 J/m²)

5 0
3 years ago
These are equal and opposite forces that do not cause a change in position or motion. True or False
Contact [7]

Answer:

TRUE

Explanation:

Balance forces are usually defined as the two distinct force that acts on an object but in opposite directions. These two acting forces are equal in size or magnitude. When this type of force is applied on any object, it signifies that the object is stationary or it is moving at a constant speed and in the same direction.

This force is comprised of two most important properties namely the strength and direction. When any of the two forces is higher then it result in the motion of the object.

Thus, the above given statement is TRUE.

3 0
4 years ago
Two forces act on an object. The first force has a magnitude of 17.0 N and is oriented 48.0° counterclockwise from the x ‑axis,
Ivanshal [37]

Answer:

Fn: magnitude of the net force.

Fn=30.11N , oriented 75.3 ° clockwise from the -x axis

Explanation:

Components on the x-y axes of the 17 N force(F₁)

F₁x=17*cos48°= 11.38N

F₁y=17*sin48° = 12.63 N

Components on the x-y axes of the  the second force(F₂)

F₂x= −19.0 N

F₂y=   16.5 N

Components on the x-y axes of the net force (Fn)

Fnx= F₁x +F₂x= 11.38N−19.0 N= -7.62 N

Fny= F₁y +F₂y= 12.63 N +16.5 N = 29.13 N

Magnitude of the net force.

F_{n} =\sqrt{(F_{nx})^{2} +(F_{ny}) ^{2} }

F_{n} =\sqrt{(-7.62)^{2} +(29.13) ^{2} }

F_{n} = 30.11N

Direction of the net force (β)

\beta =tan^{-1} (\frac{29.13}{7.62} )

β=75.3°

Magnitude and direction of the net force

Fn= 30.11N , oriented 75.3 ° clockwise from the -x axis

In the attached graph we can observe the magnitude and direction of the net force

6 0
3 years ago
Which term refers to a variable that a scientist adjusts during an experiment?
azamat

Answer:

it’s c

Explanation:

5 0
3 years ago
Early psychologists were predominately all of the following except __________. A. white B. male C. European D. wealthy
yulyashka [42]

Answer: D. wealthy

Explanation: on the e2020 test its right

7 0
3 years ago
Read 2 more answers
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