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RUDIKE [14]
3 years ago
6

What is the origin of the atomic emission spectrum of an element

Physics
1 answer:
lilavasa [31]3 years ago
5 0

Answer:

The electronic transition of an electron back to a lower energy level generates an emission spectrum.

Explanation:

The atomic emission spectrum¹ of an element has its origin when an electronic transition² occurs. An electron in an atom or ion³will absorb energy coming from a source and pass to a higher energy level, the electron, upon returning to its base state will emit a photon⁴ or a series of photons.

Hence, that leads to the formation of an emission spectrum.

Remember that an electron has energy levels in an atom or ion, at which each energy level has a specific value.

The energy values will differ from one element to another. So, it can be concluded that each element has a unique pattern of emission lines.

Key terms:        

¹Spectrum: Decomposition of light in its characteristic colors.

²Electronic transition: When an electron passes from one energy level to another, either for the emission or absorption of a photon.

³Ion: An atom electrically charged due to the gain or loss of electrons.

⁴Photon: Elementary particle that constitutes light.

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Listed following are three possible models for the long-term expansion (and possible contraction) of the universe in the absence
sineoko [7]

Answer:

From smallest ratio to the largest ratio:

Coasting Universe - Critical Universe - Recollapsing Universe(From left to right)

Explanation:

The coasting universe is one that expands at a constant rate given by the Hubble constant throughout all of cosmic time. It has a ratio of actual density to critical density that is less than 1

The critical universe is one that is at balance with no expansion .I.e. the actual density and the critical density are equal, which makes the ratio of actual density to critical density to be equal to 1

Recollapsing Universe: The expansion of the universe reverses in the future and the universe eventually recollapses. The recollapsing universe has the ratio of the actual density to the critical density to be greater than 1

7 0
2 years ago
Compare and contrast the general characteristics of a gas giant planet and one of the inner planets (such as Mercury, Earth, Ven
yKpoI14uk [10]
The gas planets usually have extremely high gravitational pulls, the surface isn't solid (since its a gas planet), and gas planets are larger than the inner planets. 
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Hope this helps.</span>
6 0
3 years ago
Determine the acceleration due to gravity for low Earth orbit (LEO) given: MEarth = 6.00 x 1024 kg, rEarth = 6.40 x 106 m, G = 6
Nana76 [90]

Answer:

The answer to the question is as follows

The  acceleration due to gravity for low for orbit is  9.231 m/s²

Explanation:

The gravitational force is given as

F_{G}= \frac{Gm_{1} m_{2}}{r^{2} }

Where F_{G} = Gravitational force

G = Gravitational constant = 6.67×10⁻¹¹\frac{Nm^{2} }{kg^{2} }

m₁ = mEarth = mass of Earth = 6×10²⁴ kg

m₂ = The other mass which is acted upon by  F_{G} and = 1 kg

rEarth = The distance between the two masses = 6.40 x 10⁶ m

therefore at a height of 400 km above the erth we have

r = 400 + rEarth = 400 + 6.40 x 10⁶ m = 6.80 x 10⁶ m

and  F_{G} = \frac{6.67*10^{-11} *6.40*10^{24} *1}{(6.8*10^{6})^{2} } = 9.231 N

Therefore the acceleration due to gravity =  F_{G} /mass  

9.231/1 or 9.231 m/s²

Therefore the acceleration due to gravity at 400 kn above the Earth's surface is  9.231 m/s²

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3 years ago
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I believe the answer you are looking for is perception.

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