Answer:
Explanation:
The net force on the potatoes is given by:
F= 52 - mgSintheta
F= 52- (2×9.8× Sin70°)
F = 52 -18.4
F= 33.58N
Using Newton's 2nd law
F = ma
a=F/m = 33.58/ 2 = 16.79m/s^2
Using the equation of motion:
V^2= u^2 + 2as
V^2 = 0 + 2× 16.79 x2
V^2 = 67.16
V=sqrt(68.16)
V= 8.195m/s This is the exit velocity of the potatoes
Kinetic energy, K.E = 1/2mv^2
KE= 1/2 × 2 × 8.195^2
KE = 67.16J
Answer:
Output power of the charger is 9.85 watts.
Explanation:
It is given that,
Output current of the USB charger, I = 1.97 A
The standard USB output voltage, V = 5 V
We need to find the output power of the charger. It can be determined using the following formula as :
P = V × I
![P=5\ V\times 1.97\ A](https://tex.z-dn.net/?f=P%3D5%5C%20V%5Ctimes%201.97%5C%20A)
P = 9.85 watts
The output power of the charger is 9.85 watts. Hence, this is the required solution.
The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5
Answer:
The velocity of the truck after the collision is 20.93 m/s
Explanation:
It is given that,
Mass of car, m₁ = 1200 kg
Initial velocity of the car, ![v_{Ci}=25\ m/s](https://tex.z-dn.net/?f=v_%7BCi%7D%3D25%5C%20m%2Fs)
Mass of truck, m₂ = 9000 kg
Initial velocity of the truck, ![v_{Ti}=20\ m/s](https://tex.z-dn.net/?f=v_%7BTi%7D%3D20%5C%20m%2Fs)
After the collision, velocity of the car, ![v_{Cf}=18\ m/s](https://tex.z-dn.net/?f=v_%7BCf%7D%3D18%5C%20m%2Fs)
Let
is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.
![initial\ momentum=final\ momentum](https://tex.z-dn.net/?f=initial%5C%20momentum%3Dfinal%5C%20momentum)
![1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v](https://tex.z-dn.net/?f=1200%5C%20kg%5Ctimes%2025%5C%20m%2Fs%2B9000%5C%20kg%5Ctimes%2020%5C%20m%2Fs%3D1200%5C%20kg%5Ctimes%2018%2B9000%5C%20kg%5Ctimes%20v)
![210000-21600=9000\ kg\times v](https://tex.z-dn.net/?f=210000-21600%3D9000%5C%20kg%5Ctimes%20v)
![v=20.93\ m/s](https://tex.z-dn.net/?f=v%3D20.93%5C%20m%2Fs)
So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.