Answer:
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Explanation:

Initially
3.0 atm 0
At equilibrium
(3.0-2p) p
Equilibrium partial pressure of 
p = 0.45 atm
The value of equilibrium constant wil be given by :


After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :

After adding 1.5 atm of
:
(2.1+1.5) atm 0.45 atm
At second equilibrium:'
(3.6-2P) (0.45+P)
The expression of equilibrium can be written as:


Solving for P:
P = 0.37 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:
= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Answer:
C
Explanation:
The reason why is beacause most of the dino's and other spices that were here before humanity are exctinct. Some are still alive and have evovled into something greater such as a crocidile, and many other repitlians
Hope this helps!
Pls mark brainlest!
Answer:
The answer is
<h2>3.68 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
<h3>

</h3>
From the question
mass of substance = 12.50 g
volume = 3.4 mL
The density of the substance is

We have the final answer as
<h3>3.68 g/mL</h3>
Hope this helps you
Answer:
Energy produced by the chip =10,460 Joules.
Explanation:
The specific heat of water is one calorie/gram ° C = 4.186 joules/gram ° C, which is higher than any other common substance. As a result, water plays a very important role in regulating temperature. The specific heat per gram for water is much greater than that of a metal, as described in the water-metal example. Replace the mass (m), the temperature change (ΔT), and the specific heat (c) of the solution in the equation Q = c x m x ΔT, where Q is the heat absorbed by the solution. For specific heat of water we goes as given in the question 4,184 J/kg°C
Q =4184×0.5×(25-20)
=10,460 Joules.
Thus heat gained by water (Q)= Energy produced by the chip =10,460 Joules.