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ella [17]
3 years ago
12

Different microscopic organisms cause different

Chemistry
1 answer:
lozanna [386]3 years ago
5 0

Answer/Explanation:

A theory has lots of scientific evidence to back it up. We know this to be true based on lots of different diseases and studies of their spread.

A hypothesis is more of a starting point - an educated guess based on limited evidence. It requires further testing before becoming a theory.

A law is something that can be generalized to lots of contexts, and is universal. Such as the law of thermodynamics.

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In the following reaction, what is the effect of adding more NO2 to the starting reaction mixture?
Mars2501 [29]

Answer:

It would increase the final quantity of products

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

2NO₂ ⇄ N₂O₄

In this reaction the equilibrium is disturb by increasing the concentration of reactant.

When the concentration of reactant is increased the system will proceed in forward direction in order to regain the equilibrium. Because when reactant concentration is high it means reaction is not on equilibrium state. As the concentration of NO₂ increased the reaction proceed in forward direction to regain the equilibrium state and more product is formed.

5 0
3 years ago
Can anyone solve this?
Sonja [21]

Answer:

3P2O5:

P:6 O:15

5CO2

C:5 O:10

3C6H12O6

C:18 H:36 O:18

4C6H12

C:24 H:48

3Mg3(PO4)2

Mg:9 P:2 O: 8

4(NH4)2S

N:8 H:32 S:4

4 0
3 years ago
Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.
attashe74 [19]

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
8 0
3 years ago
I need the answers to this and to see if what I put is right so far
klemol [59]

1) B+3 is ok. The exercise already put B+3. What

-------------------------------------------------------------------------------------------------------------------

2) Ge is a neutral atom because it doesn't have any charge.

Germanium has 32 electrons and 32 protons because its atomic number is 32.

Be careful with that.

Neutral atoms have the same numbers of electrons and protons.

-------------------------------------------------------------------------------------------------------------------

3)

5 0
10 months ago
An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr
Lera25 [3.4K]

Answer:

\sigma_y\ =210.2\ MPa  

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}

\sigma_y\ =Yield\ strength

d = diameter

K =Constant

\sigma_o\ =material\ constant

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

163=\sigma_o+\dfrac{K}{\sqrt 35}      ------------1

d= 17 μm ,yield strength = 192 MPa

192=\sigma_o+\dfrac{K}{\sqrt 17}           ------------2

From equation 1 and 2

192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}

K=394.53

By putting the values of K in equation 1

163=\sigma_o+\dfrac{394.53}{\sqrt 35}

\sigma_o\ =96.31\ MPa

\sigma_y=96.31+\dfrac{394.53}{\sqrt d}

Now when d= 12 μm

\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}

\sigma_y\ =210.2\ MPa

4 0
3 years ago
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