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salantis [7]
3 years ago
7

I have a 4 amino acid peptide of unknown sequence with a curious titration profile around pH = 6. If Iknow that the peptide N-te

rminus has a pKa = 9, C-terminus pKa = 3, and an obvious titration point at pH= 10.5, what amino acid could likely generate a strange titration profile at pH 6 in this peptide?a. Cysteineb. Tyrosinec. Histidined. Arginine
Chemistry
1 answer:
netineya [11]3 years ago
4 0

Answer:

c. Histidine

Explanation:

Histidine is a compound that is normally used for the generation of protein. Three amino acids commonly have basic side chain when the pH is neutral. The conjugate acid in histidine has a pKa of approximately 6. Based on the description of the experimental analysis provided in the statement, the right option is option c.

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Compare the potential energy of two atoms chemically bonded to their potential energy when separated.
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Answer:

See explanation

Explanation:

The essence of chemical bonding is in order to attain minimum energy. The minimum energy state is the most stable state of a chemical system.

As the distance of separation between atoms decreases, the potential energy of the system decreases accordingly.

An optimum distance is reached when the two atoms attain the lowest potential energy. This is designated as the bond distance of the two atoms.

Hence two atoms have lower potential energy when bonded than when separated at large distance.

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Answer:

320

Explanation:

8*8*5

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There have been different models of the atom over time. How has the competition between these models affected our understanding
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Consider the following intermediate reactions.
Alja [10]

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

4 0
3 years ago
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An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li
tatiyna

Answer:

1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

m = m_2 - m_1 = 105.22g - 80.21 g = 25.01 g

Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

\rho = \frac{m}{V} = \frac{25.01g}{20.14mL} = 1.242 g/mL

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3 years ago
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