I'm not sure if what this question is asking but ill be assuming that the average molecular mass is required. An assuming that the abundance of each isotope is 50% the average molecular mass is 69.82 amu.
Iconic +covalent is the answer to this
Answer : The
for this reaction is, -88780 J/mole.
Solution :
The balanced cell reaction will be,
![Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)](https://tex.z-dn.net/?f=Cu%28s%29%2B2Ag%5E%2B%28aq%29%5Crightarrow%20Cu%5E%7B2%2B%7D%28aq%29%2B2Ag%28s%29)
Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
The half oxidation-reduction reaction will be :
Oxidation : ![Cu\rightarrow Cu^{2+}+2e^-](https://tex.z-dn.net/?f=Cu%5Crightarrow%20Cu%5E%7B2%2B%7D%2B2e%5E-)
Reduction : ![2Ag^++2e^-\rightarrow 2Ag](https://tex.z-dn.net/?f=2Ag%5E%2B%2B2e%5E-%5Crightarrow%202Ag)
Now we have to calculate the Gibbs free energy.
Formula used :
![\Delta G^o=-nFE^o](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D-nFE%5Eo)
where,
= Gibbs free energy = ?
n = number of electrons to balance the reaction = 2
F = Faraday constant = 96500 C/mole
= standard e.m.f of cell = 0.46 V
Now put all the given values in this formula, we get the Gibbs free energy.
![\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D-%282%5Ctimes%2096500%5Ctimes%200.46%29%3D-88780J%2Fmole)
Therefore, the
for this reaction is, -88780 J/mole.
Answer:
is this true/false? if so its true.
Explanation: