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1 year ago

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Physics

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natita [175]1 year ago

8 0

(a) The average velocity of the car in m/s for the first leg of the run is 36.2 m/s.

(b) The average velocity (in m/s) for the total trip is 0.

<h3>Average velocity </h3>

The average velocity of the car in m/s for the first leg of the run is calculated as follows;

Average velocity = total displacement/total time

Average velocity = (760) / (21) = 36.2 M/S

<h3>Average velocity for total trip</h3>

The average velocity (in m/s) for the total trip is calculated as follows;

v = total displacement/total time

v = 0/(26 + 21)

v = 0

Thus, the average velocity of the car in m/s for the first leg of the run is 36.2 m/s.

The average velocity (in m/s) for the total trip is 0.

Learn more about average velocity here: brainly.com/question/6504879

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