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ipn [44]
2 years ago
5

Visualizing the body in the position is significant because all observers have a common point of reference when describing and d

iscussing its regions.
Physics
1 answer:
FromTheMoon [43]2 years ago
6 0

Visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.

<h3>What is the anatomical position?</h3>
  • Anatomical position, also known as conventional anatomical position, refers to the body's position while it is standing erect and looking forward, with each arm hanging on either side of the body and palms facing forward.
  • The legs are parallel, with the feet level on the floor and forward facing.
  • When explaining particular anatomical words and locations in human anatomy and physiology, the anatomical position is a standard point of reference.
  • Visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.

As the description itself says, visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.

Therefore, visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.

Know more about the anatomical position here:

brainly.com/question/5029605

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The question you are looking for is given here:

Visualizing the body in the _____________ is significant because all observers have a common point of reference when describing and discussing its region.

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I rent a small high pressure water sprayer to clean the outside of my house. The sprayer works like a super soaker with a hose b
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Answer:

1. 80,000 Pa

2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, P=hg\rho

Where h is the height that water is to reach, g is gravitational constant and \rho is the density, in this case, we assume \rho of pure water as 1000 Kg/m^3

Assuming g=10 m/s^{2}

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<u>Question 2</u>

Pressure can also be found by the formula

P=0.5v^{2}\rho where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

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v=11.3 m/s

<u>Question 3</u>

As already illustrated

v=\sqrt 2hg

Taking g as 9.8 and h now is 8m

v=\sqrt 2*8*9.8

v=12.52198067

Rounding off to 1 decimal place

v=12.5 m/s

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3 years ago
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