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3 years ago

HELP ME PLEASEEEEEEEEEEEEEEE

Physics

1 answer:

mezya [45]3 years ago

7 0

Answer:

KE = 1/2 M V^2 Equation to express kinetic energy

Since the result depends linearly on M and to the second power on V,

V has greater effect on the result.

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A 43 kg girl and a 7.1 kg sled are on the frictionless ice of a frozen lake, 12 m apart but connected by a rope of negligible ma

trapecia [35]

Answer:

(a) Girl acceleration = 0.15 m/s², (b) Sled acceleration = 0.93 m/s²

Explanation:

Given:

M1=Mass of girl = 43 Kg

M2= mass of Sled = 7.1 Kg

Force F= 6.6 N

To Find (a) a1 = girl acceleration (b) a2 = sled acceleration

Solution:

F1 = F2 = F (Newton's 3rd Law)

F=ma (Newton's 2nd Law)

(a) F = M1a1

⇒a1 = F/M1 = 6.6 N / 43 Kg = 0.15 m/s²

(b) a2 = F / M2 = 6.6 N / 7.1 Kg = 0.93 m/s²

6 0

3 years ago

Drinking water helps your body maintain

8090 [49]

Drinking water helps maintain nearly all processes of the human body and <em>homeostasis. </em>Further, drinking water helps,

Digestion
Absorption
Circulation
Saliva and mucus production
Thermoregulation/homeostasis
Lubrication of joints
Boosts integumentary health.
Helps in excretory systems
Prevents dehydration of cells
Reduces chance of hangover from alcoholic drinks.
etc,

Succinctly, it is VERY important to drink water! Water is the source of human life and without water, we cannot survive.

6 0

3 years ago

The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .

vlabodo [156]

Answer: $90\°$

Explanation:

The Compton Shift $\Delta \lambda$ in wavelength when the photons are scattered is given by the following equation:

$\Delta \lambda=\lambda_{c}(1-cos\theta)$ (1)

Where:

$\lambda_{c}=2.43(10)^{-12} m$ is a constant whose value is given by $\frac{h}{m_{e}c}$ , being $h$ the Planck constant, $m_{e}$ the mass of the electron and $c$ the speed of light in vacuum.

$\theta)$ the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through $180\°$ :

$\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))$ (2)

$\Delta \lambda_{max}=\lambda_{c}(1-(-1))$

$\Delta \lambda_{max}=2\lambda_{c}$ (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

$\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)$ (4)

$\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)$ (5)

If we want $\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}$ , $1-cos\theta$ must be equal to 1:

$1-cos\theta=1$ (6)

Finding $\theta$ :

$1-1=cos\theta$

$0=cos\theta$

$\theta=cos^{-1} (0)$

Finally:

$\theta=90\°$ This is the scattering angle that will produce $\frac{1}{4}\Delta \lambda_{max}$

7 0

3 years ago

Having the correct posture and the degree or severity of braking, acceleration and steering inputs have a direct result on the a

kaheart [24]

Answer: Vehicle Balance

Explanation:

Vehicle balance simply means how the weight of a vehicle is distributed across its tires which connects to the road

It should be noted that there'll be a shift in the balance of a vehicle when the braking, acceleration, or turning bring about a scenario in which the weight of th vehicle moves from one area to another.

8 0

3 years ago

A frictionless piston-cylinder device contains 4.5 kg of nitrogen at 110 kPa and 200 K. Nitrogen is now compressed slowly accord

pochemuha

Answer:

427.392 kJ

Explanation:

m = Mass of gas = 4.5 kg

Initial temperature = 200 K

Final temperature = 360 K

R = Mass specific gas constant = 296.8 J/kgK

$\gamma$ = Specific heat ratio = 1.5

Work done for a polytropic process is given by

$W=\frac{mR\Delta T}{1-\gamma}\\\Rightarrow W=\frac{4.5\times 296.8(360-200)}{1-1.5}\\\Rightarrow W=-427392\ J\\\Rightarrow W=-427.392\ kJ$

The work input during the process is -427.392 kJ

3 0

4 years ago