2 years ago

9.00 V is applied to a wire with a

Physics

1 answer:

Ulleksa [173]2 years ago

8 0

Answer:

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How does Doppler ultrasound technology differ from ultrasound technology

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. Doppler ultrasound is based on absorption of sound, and other

ultrasound technology is based on reflection.D.

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3 years ago

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Which of the following is not a reason fluorescent lamps are advantages over incandescent lamps?

iren2701 [21]

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3 years ago

Potential difference is measured in which units? volts amps currents watts

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A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr

astraxan [27]

Answer:

x = 0.0734 m = 7.34 cm

Explanation:

First we shall calculate the area of the piston:

$Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2$

Now, we will calculate the force on the piston due to atmospheric pressure:

$Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N$

Now, for the compression of the spring we will use Hooke's Law as follows:

$F = kx\\$

where,

k = spring constant = 3400 N/m

x = compression = ?

Therefore,

x = 0.0734 m = 7.34 cm

8 0

3 years ago

A sound source emits 20.0 W of acoustical power spread equally in all directions. The threshold of hearing is 1.0 × 10-12 W/m2.

ahrayia [7]

Answer:

0.0018 W/m²

Explanation:

Power and intensity are related as:

$I=\frac{P}{4\pi r^2}$

P= 20.0 W (given)

r = 30.0 m (given)

$I=\frac{20.0}{4\pi(30.0)^2}=0.0018 W/m^2$

Intensity in decibels:

$I(dB)=10log\frac{I}{I_o}\\=10log\frac{0.0018}{10^{-12}}=92.5 dB$

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3 years ago