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Marina CMI [18]
3 years ago
14

50 The emissivity of galvanized steel sheet, a common roofing material, is s = 0.13 at temperatures around 300 K, while its abso

rptivity for solar irradiation is aS = 0.65. Would the neighborhood cat be comfortable walking on a roof constructed of the material on a
(
a. If a dryer is designed to operate with an electric power consumption of Pelec = 500 W and to heat air from an ambient temperature of Ti = 20°C to a discharge temperature of To = 45°C, at what volu- metric flow rate 'e should the fan operate? Heat loss from the casing to the ambient air and the surround- ings may be neglected. If the duct has a diameter of D = 70 mm, what is the discharge velocity Vo of the air? The density and specific heat of the air may
day when GS = 750 W/m2, T00 = 16°C, and h = 7

W/m2 · K? Assume the bottom surface of the steel is

insulated.
be approximated as p = 1.10 kg/m3 and cp

J/kg · K, respectively.
Physics
1 answer:
denis-greek [22]3 years ago
4 0
Since the power is already given together with the initial and final temperature, the heat by convection and conduction should be determined.
Heat by convection can be determined using
qh = hAΔT
and the conduction is
qc =kAΔT
Which can be combined to determine the flow rate of air using
mcpΔT
and the mass flow rate can be converted to volumetric flowrate using the specific gravity of the air.
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What must exist for the engineering process to begin?
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Image from a far away object formed by a concave mirror

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a cyclist coasting down a 5.0 ◦ incline at a constant speed of 6.0 km/h because of air resistance. If the total mass of the bicy
Dvinal [7]

Answer:

F_{net}= 85.41\ N

Explanation:

mass of the bicycle + cyclist = 50 kg

constant speed = 6 km/h

a cyclist coasting down a 5.0° incline

the downward velocity is constant, so net acceleration must be zero

the air drag must be equal to gravitational force downward along the ramp

F_a = mg sin \theta  

now for upward motion

F_{net} = mg sin \theta + air\ drag

F_{net} = mg sin \theta + mg sin \theta

F_{net} = 2 mg sin \theta

F_{net} = 2\times 50 \times 9.8 sin 5^0

F_{net}= 85.41\ N

3 0
4 years ago
a spring is stretched 20 cm by a 30.0 n force. determine the work done in stretching the spring from 0 to 40 cm?
Alekssandra [29.7K]

The work done when a spring is stretched from 0 to 40cm is 4J.

What is work done?

Work done is the magnitude of force multiplied by displacement of an object. It is also the amount of energy transferred to an object when work is done on that.

The work done on the spring to stretch to 40cm is,

F = kx

where F is force, k is force constant.

k = F / x = 10 N / 20 * 10^-2 m = 50 N/m

W = 0.5 * k * (x)^2

where W = work done, k = force constant.

W = 0.5 x 50 x (40 x 10^-2)^2 = 4 J.

Therefore, the work done on the spring when it is stretched to 40cm is 4J.

To learn more about work done click on the given link brainly.com/question/25573309

#SPJ4

3 0
1 year ago
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