Answer:
Two slender woolen sweaters are hotter than a thick woolen sweater in light of the fact that there is a layer of air between them that doesn't permit our body warmth to get away yet it likewise it doesn't retains heat from the climate and fleece is additionally a protector that itself doesn't permit our body warmth to get away
Answer:
1.5×10⁷ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength of radio wave (λ) = 20 m
Frequency (f) =?
Frequency and wavelength of a wave are related by the following equation:
v = λf
Where:
'v' is the velocity of electromagnetic wave.
'λ' is the wavelength
'f' is the frequency.
With the above formula, we can obtain the frequency of the radio wave as illustrated below:
Wavelength of radio wave (λ) = 20 m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 20 × f
Divide both side by 20
f = 3×10⁸ / 20
f = 1.5×10⁷ Hz
Thus the frequency of the radio wave is 1.5×10⁷ Hz
Lol. It is now a solution and not really inseparable, so your only logical option would be to throw it away and try again.
Answer: The volume of the balloon at the center of the typhoon is 41.7L.
Note: The complete question is given below;
If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?
The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.
Explanation:
Since no temperature changes were given, it is assumed to be constant. Therefore, Boyle's law which describes the relationship between pressure and volume is used to determine the new volume at the center of Typhoon Odessa. Mathematically, Boyle's law states that; P1V1 = P2V2
Assuming 1atm = 1 bar, 1mbar = 0.001atm, 40mbar = 0.040atm
P1 = 1.0atm, V1 = 40.0L, P2 = 1atm - 0.040atm = 0.960atm, V2 = ?
Using P1V1 = P2V2
V2 = P1V1/P2
V2 = 1.0 * 40.0 / 0.96
V2 = 41.67L
Therefore, the volume of the balloon at the center of the typhoon is 41.7L.
