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Nataly [62]
3 years ago
13

A 20 N south magnetic force pushes a charged particle traveling with a velocity of 4 m/s west through a 5 T magnetic field point

ing downwards . What is the charge of the particle ?
Physics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>

Explanation:

Force, F:

{ \bf{F=BeV}}

F is magnetic force.

B is the magnetic flux density.

e is the charge of the particle.

V is the velocity

{ \sf{20 = (5 \times e \times 4)}} \\ { \sf{20e = 20}} \\ { \sf{e = 1 \: coulomb}}

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An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
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In other words, a body performs a u.a.r.m when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases uniformly.

In this case, the position is calculated using the expression:

x = xo + vo*t + ½*a*t²

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  • v0 is the initial velocity.
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  • t is the time interval in which the motion is studied.

In this case:

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Solving:

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