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andriy [413]
3 years ago
10

When you throw a ball, the work you do to accelerate it equals the kinetic energy the ball gains. if you do twice as much work w

hen throwing the ball, does it go twice as fast? explain?
Physics
1 answer:
nata0808 [166]3 years ago
8 0
It doesn't because when u threw it the first time, u notice that the ball eventually came to a stop because of the force that was acting upon it. Although when u throw it harder it will start out faster than the first time u threw it because u put more kinetic energy onto the ball. But the same thing happens with this ball that happened to the second ball, they both have a type of force acting upon them.
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4 0
4 years ago
Please help me :) ty
slega [8]
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Explanation:
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8 0
4 years ago
Read the passage.
Paladinen [302]
<h2>Answer: B)Scientists’ understanding of cells continually improved as the results of studies built upon each other over time and formed the cell theory.</h2>

Explanation:

Nowadays we know <u>cells are essential microscopic units that make up the living beings, capable of reproducing independently. </u>

However, this is the result of a long process of discoveries and studies made since the 19th century, in which the continuous improvement of new technologies was helpful.

In fact, it is wel known the English scientist Robert Hooke was the first to discover the existence of cells by looking through a compound microscope at a cork sheet, realizing that it was made up of small polygonal holes (like those of a honeycomb) that reminded him of the chambers in which the monks stayed (called cells). Then, during the next centuries more studies were made until we had the current knowledge about the structure of a cell.

7 0
3 years ago
Suppose a 60-kg boy and a 41-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration
Digiron [165]

Answer:

Approximately 2.05\; {\rm m\cdot s^{-2}}.

Explanation:

The net force on the girl would be:

\begin{aligned}m(\text{girl}) \, a(\text{girl}) &= 41\; {\rm kg} \times 3.0\; {\rm m\cdot s^{-2}} \\ &= 123.0\; {\rm N} \end{aligned}.

Under the assumptions, the net force on this girl would be equal to the tension force in the rope. All other forces on the girl would be balanced.

In other words, the tension force that the rope exerted on the girl would be 123.0\; {\rm N}. The girl would exert a reaction force on the rope at the same magnitude (123.0\; {\rm N}\!) in the opposite direction. This force would translate to a 123.0\; {\rm N}\!\! force on the boy towards the girl.

Under similar assumptions, the net force on the boy would also be 123.0\; {\rm N}. Since the mass of the boy is m(\text{boy}) = 60\; {\rm kg}, the acceleration of the boy would be:

\begin{aligned}a(\text{boy}) &= \frac{(\text{net force})}{m(\text{boy})} \\ &= \frac{123.0\; {\rm N}}{60\; {\rm kg}} \\ &= 2.05\; {\rm m\cdot s^{-2}}\end{aligned}.

3 0
2 years ago
A challenge gaining prominence throughout the planet is the increased need for \"green\" or sustainable energy. in certain parts
Inga [223]

32.6% of 1.4 Mw

= (0.326) x (1,400,000 joules/second)

=  456,400 joules/second .


1 year

=  (365 da) x (86,400 sec/da)  =  31,536,000 seconds


(456,000 joules/sec) x (31,536,000 sec)  =  1.438 x 10¹³ Joules 

(That's 1.438 x 10⁷ Megajoules, or 3,994,560 kWh)


5 0
4 years ago
Read 2 more answers
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