Answer:
I say the statement is true
The mass of carbon dioxide that would be produced will be 22 kg
<h3>Combustion of carbon</h3>
The combustion of carbon in air can be represented by the equation:
C + O2 ---> CO2
The mole ratio of C to O2 to CO2 is 1:1:1.
Mole of 6kg of carbon = mass/molar mass
= 6000/12
= 500 moles
Equivalent mole of CO2 produced = 500 moles
Mass of 500 moles CO2 = mole x molar mass
= 500 x 44.01
= 22,005 g or 22 kg approximately
More on combustion reactions can be found here: brainly.com/question/13649083
Chemical properties are mainly determined by the number of valence electrons (electrons which can be gained, lost, or shared) in the atom.
Answer : The limiting reactant is 
Explanation : Given,
Mass of 
= 30.0 g
Mass of = 75.0 g
Molar mass of = 44 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 5 mole of react with 1 mole of
So, 2.34 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Therefore, the limiting reactant is
The correct answer is "greenhouse gases." Certain gases in the atmosphere, like carbon dioxide, nitrous oxide, and methane, absorb heat and prevent it from escaping into space. These gases are called greenhouse gases.
