Answer:
In this diagram, the phenomenon moving from medium A which represents water to medium B that represents air is called refraction.
Explanation:
Refraction takes place when light passes through a water surface due to its refractive index which is 1.33. Air possesses a refractive index of about 1. Looking at the phenomenon moving between medium A and B, it seems to bend at the water's surface. This happens because of the bending of the light rays as they move from the water to the air. The time when the rays reach the eyes, the eyes trace them back as straight lines or lines of sight. These lines divide at a higher position than where the actual rays originated. This causes the phenomenon to appear higher and the water to appear shallower than what it is in reality.
Answer:Sublimation is the conversion between the solid and the gaseous phases of matter, with no intermediate liquid stage. For those of us interested in the water cycle, sublimation is most often used to describe the process of snow and ice changing into water vapor in the air without first melting into water.
Explanation:
Answer:
The dissociation of copper sulfate into ions is an exothermic chemical reaction that releases heat into the surroundings.
Explanation:
Some of the potential energy stored in the solid sample of anhydrous copper sulfate is released as heat as the sample dissolves and dissociates into ions in the water. This is due to the large lattice energy of the crystalline copper sulfate.
hope this helps
Answer:
36.2874 $
Explanation:
1 ton = 907.185 kilograms.
907.185 x 0.04 =
36.2874
<em>-kiniwih426</em>
Answer:
3.336.
Explanation:
<em>Herein, the no. of millimoles of the acid (HCOOH) is more than that of the base (NaOH).</em>
<em />
So, <em>concentration of excess acid = [(NV)acid - (NV)base]/V total</em> = [(30.0 mL)(0.1 M) - (29.3 mL)(0.1 M)]/(59.3 mL) = <em>1.18 x 10⁻³ M.</em>
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<em> For weak acids; [H⁺] = √Ka.C</em> = √(1.8 x 10⁻⁴)(1.18 x 10⁻³ M) = <em>4.61 x 10⁻⁴ M.</em>
∵ pH = - log[H⁺].
<em>∴ pH = - log(4.61 x 10⁻⁴) = 3.336.</em>
