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ASHA 777 [7]
3 years ago
13

When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find

the number of moles of oxygen that are needed to form 6 mol of Fe2O3.
Chemistry
1 answer:
Art [367]3 years ago
6 0
 when iron and oxygen the reactin form Fe2O3 balance equation for this is  <span>4Fe + 3O2---> 2Fe2O3 
9moles of O2 are needed to produce 6mol of Fe2O3 since the ratio of oxygen to iron(II)oxide is 3:2 
                               hope its help</span>
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3 years ago
Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange
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Answer:

A. 10.0 grams of ethyl butyrate would be synthesized.

B. 57.5% was the percent yield.

C. 7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

Explanation:

CH_3CH_2CH_2CO_2H(l)+CH_2CH_3OH(l)+H^+\rightarrow CH_3CH_2CH_2CO_2CH_2CH_3(l)+H_2O(l)

A

Moles of butanoic acid = \frac{7.60 g}{88 g/mol}=0.08636 mol

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

\frac{1}{1}\times 0.08636 mol=0.08636 mol of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 100%

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

100\%=\frac{\text{Experimental yield}}{10.0 g}\times 100

Experimental yield = 10.0 g

10.0 grams of ethyl butyrate would be synthesized.

B

Theoretical yield of ethyl butyrate  = 10.0 g

Experimental yield ethyl butyrate = 5.75 g

Percentage yield of the reaction = ?

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{5.75 g}{10.0 g}\times 100=57.5\%

57.5% was the percent yield.

C

Moles of butanoic acid = \frac{7.60 g}{88 g/mol}=0.08636 mol

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

\frac{1}{1}\times 0.08636 mol=0.08636 mol of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 78.0%

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

78.0\%=\frac{\text{Experimental yield}}{10.0 g}\times 100

Experimental yield = 7.80 g

7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

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Answer:

  • The<em> diagram</em> with the five<em> labels</em> of the parts is in the image attached. Please, see the image.

Explanation:

<u>1) General explanation:</u> a <em>potential chemical energy diagram</em> is used to show how the <em>reactants</em> gain energy until they reach the <em>activation energy</em>, form the <em>activated complex</em>, and release part of the energy to form the <em>products</em>.

The difference between the chemical potential energy of the products and the reactants is the <em>enthalpy of the reaction</em>:

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The labels that correspond to each part of the diagram are explained next.

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<u><em>5) Products:</em></u>

These are the substances formed when the reaction is completed. They are lower in energy than the activated complex. They can be either higher or lower in energy than the reactants. The products are shown to the right of the diagram.

<em><u>6) Enthalpy of the reaction:</u></em>

The enthalpy of the reaction is the difference in energy of the products and the reactants. In this case, since, the products are higher in energy, it means that the reaction absorbed energy and it is an endothermic reaction.

4 0
3 years ago
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