There are 2 significant figures in this number. A significant figure is any number that isn’t 0. Hope this helps.
It helps shape and create the study of electromagnetism
Equilibrium equation is
<span>Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) </span>
<span>From the reaction equation above, the formula for Ksp: </span>
<span>Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 </span>
<span>You know [CO32-], so you can solve for [Ag+] as: </span>
<span>(8.1 x 10^-12) = [Ag+]^2 (0.025) </span>
<span>[Ag+]^2 = 3.24 x 10^-10 </span>
<span>[Ag+] = 1.8 x 10^-5 M </span>
Answer: the answer is b: sp3d
Explanation: BrF3 has a Bent T shaped structure with Br as a central atom bonded with three F atoms (three bond pairs) and two lone pairs. Hence , the hybridization would be sp3d. Br atom has 7 electron in its outer most shell. After the bond formation of BrF3 molecule we have 3 bond pairs+ 2 lone pairs
Since Qp>Kp , the reaction is not at equilibrium.
<h3>What is the equilibrium constant?</h3>
The equilibrium constant shows the extent to which reactants are converted into products.
Now we have to obtain the Qp as follows;
Qp =[CH3OH]/[CO] [H2]^2
Qp = 0.265/(0.265) (0.265)^2
Qp = 14.2
Now we know that Kp = 6.09×10−3, Since Qp>Kp , the reaction is not at equilibrium.
Learn more about equilibrium constant:brainly.com/question/10038290
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