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Semenov [28]
2 years ago
6

Sulfur has an oxidation number of +6 in which two formulas?

Chemistry
1 answer:
sp2606 [1]2 years ago
5 0
<h3>Answer:</h3>

\sf \blue{B. H_{2}SO4 \: and \: SO_{2}}

<h3>Explanation:</h3>

As we know in oxidation, oxygen is added and hydrogen is reduced. And in option B, we can observe that is oxygen added +6. So, we conclude that option B is valid.

<h3>Hope it help you</h3>
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Ne4ueva [31]
6 . 2 in its inner shell & the remaining 6 in its outer shell.
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3 years ago
Please help me, I really don't want to fail but I don't know how to do this
Brrunno [24]

Answer:

A)

<u>4, 7, 4, 6</u>

B)

<u>12 moles</u>

Explanation:

NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)

__↑______↑

8.00 mol | 14.00 mol

________________

NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)

You can turn this into a system of variables which are solvable.

To do this, create variables for the coefficients of each compound in the reaction respectively.

a(NH_{3}(g)) + b(O_{2}(g)) → \\c(NO_{2}) + d(H_{2}O(g))

Because to be balanced, the count of atoms in each element of the compound correspond to the coefficient of the variable in that compound so that the count of the left (reactant) side is set equal to the right (product) side.

a corresponds to the coefficient of the first compound, b corresponds to the coefficient of the second compound, c corresponds to the coefficient of the third compound, and d corresponds to the coefficient of the fourth compound.

(Reactant = Product)

Reactant: 1a [N] Product: 1c.

Reactant: 3a [H] Product: 2d.

Reactant: 2b [O] Product: 2c + 1d.

Thus the system is:

1a = 1c

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2b = 2c + 1d.

Then just use the substitution methods to solve.

3 0
2 years ago
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Answer:

Hey there!

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Let me know if this helps :)

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3 years ago
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We are given
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Solve for P<span />
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