Round 89 to 90 then divide by 4. so its 24.
Answer:
The empirical formula is .
Explanation:
Given that, the combustion of 29.5 mg produced 80.2 mg CO₂ and 16.4 mg of H₂O.
Mass of C
g
Mass of H
g
Mass of O =
g
Number of mole of C
mol
Number of mole of H
mol
Number of mole O
mol
Dividing by lowest integer
The empirical formula is .