Answer:
339.2K
Explanation:
Using Charles law equation;
V1/T1 = V2/T2
Where;
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
V1 = 2.97 L
V2 = 3.42 L
T1 = 21.6°C = 21.6 + 273 = 294.6K
T2 = ?
Using V1/T1 = V2/T2
2.97/294.6 = 3.42/T2
Cross multiply
2.97 × T2 = 294.6 × 3.42
2.97T2 = 1007.532
T2 = 1007.532 ÷ 2.97
T2 = 339.236
The final temperature is 339.2K
Respuesta:
4.42 × 10⁻⁶ m³
Explicación:
Paso 1: Información provista
- Densidad del osmio (ρ): 22600 kg/m³
Paso 2: Convertir 100 g a kilogramos
Usaremos el factor de conversion 1 kg = 1000 g.
100 g × 1 kg/1000 g = 0.100 kg
Paso 3: Calcular el volumen ocupado por 0.100 kg de osmio
La densidad es una propiedad intensiva, igual al cociente entre la masa y el volumen.
ρ = m/V
V = m/ρ
V = 0.100 kg / (22600 kg/m³) = 4.42 × 10⁻⁶ m³
Answer:
D. 15g
Explanation:
The law of conservation of mass states that, in a chemical reaction, mass can neither be created nor destroyed. This means that the amount of matter in the elements of the reactants must be equal to the amount in the resulting products.
In this question, 25 grams of a reactant AB, was broken down in a reaction to produce 10 grams of products A and X grams of product B. According to the law of conservation of mass, the mass of the reactant must be equal to the total mass of the products. This means that 25 grams must also be the total mass of both products in this reaction. Hence, if product A is 10 grams, product B will be 25 grams - 10 grams = 15 grams.
Therefore, product B must be 15 grams in order to form a total of 25 grams when added to the mass of product A. This will equate the mass of the reactant AB and fulfill the law of conservation of mass.
