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Luden [163]
3 years ago
14

The air in a 2 L balloon at 0.998 atm and 34.0 °C. What will be its pressure if it is brought to a higher altitude where it now

occupies 3.5 L and is at 12.0 °C?
Chemistry
1 answer:
Phantasy [73]3 years ago
4 0

Answer: 0.529 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.998 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2 L

V_2 = final volume of gas = 3.5 L

T_1 = initial temperature of gas = 34.0^oC=273+34.0=307.0K

T_2 = final temperature of gas = 12.0^oC=273+12.0=285.0K

Now put all the given values in the above equation, we get:

\frac{0.998\times 2}{307.0K}=\frac{P_2\times 3.5}{285.0K}

P_2=0.529atm

Thus the pressure if it is brought to a higher altitude where it now occupies 3.5 L and is at 12.0 °C is 0.529 atm

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