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Lyrx [107]
2 years ago
12

A handsfree device may be used if it can be activated or deactivate with a?

Engineering
1 answer:
NeX [460]2 years ago
7 0

A handsfree device may be used if it can be activated or deactivate with a cellphone.

<h3>What is hands-free?</h3>

Handsfree is a device which when connected to a cell device can be used in listening to audio, video and messages.

A driver can also activate or deactivate with a swipe when connect to the vehicle audio device.

Therefore,

A handsfree device may be used if it can be activated or deactivate with a cellphone.

Learn more on handsfree below

brainly.com/question/12253610

#SPJ1

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A turbojet is flying with a velocity of 900 ft/s at an altitude of 20,000 ft, where the ambient conditions are 7 psia and 10°F.
tino4ka555 [31]

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

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3 0
4 years ago
A tensile test was made on a tensile specimen, with a cylindrical gage section which had a diameter of 10 mm, and a length of 40
tamaranim1 [39]

Answer:

The answers are as follow:

a) 10 mm

b) 12.730 N/mm^{2}

c) 127.307 N/mm^{2}

d) 0.25

Explanation:

d1 = 10mm , L1 = 40 mm, L2 = 50 mm, reduction in area = 90% = 0.9

Force = F =1000 N

let us find initial area first, A1 = pi*r^{2} = 78.55 mm^{2}

using reduction in area formula : 0.9 = (A1 - A2 ) / A1

solving it will give,  A2 = 0.1 A1 = 7.855  mm^{2}

a) The specimen elongation is final length - initial length

50 - 40 = 10 mm

b) Engineering stress uses the original area for all stress calculations,

Engineering stress = force / original area  = F / A1 = 1000 / 78.55  

Engineering stress = 12.730 N / mm^{2}

c) True stress uses instantaneous area during stress calculations,

True fracture stress = force / final  area  = F / A2 = 1000 / 7.855

True Fracture stress = 127.30 N / mm^{2}

e) strain = change in length / original length

strain = 10 / 40  = 0.25

8 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
enyata [817]

Answer:

Check image, right on PLATO

Explanation:

7 0
3 years ago
All arrived at an uncontrolled intersection at the same time. which has the right-of-way?:
Molodets [167]

If two vehicles arrive at an uncontrolled intersection almost simultaneously, the driver of the car that arrived at the intersection last must give the right of way. The driver on the left has the right of way if you both arrive at the intersection at the same moment.

Which driver should yield at an uncontrolled T-intersection?

The driver of the car turning must give way to all oncoming cross traffic when two cars are approaching an uncontrolled "T" crossroads. You need to stop and give way to vehicles and pedestrians while entering a public road from a driveway or private road.

What is right of way?

When two vehicles or pedestrians are approaching from opposite directions, moving at a speed, and close enough to create a collision, one has the right to move forward legally before the other, unless the other gives way.

Learn more about uncontrolled intersection: brainly.com/question/14312150

#SPJ4

4 0
2 years ago
What is the impedance of a 5μF capacitor at a frequency of 500Hz? What is the impedance of a60mH inductor at this frequency?
choli [55]

Answer:

1) 63.66 ohm

2) 188.49 ohm

Explanation:

Data provided in the question:

Part 1

Capacitance, C = 5μF = 5 × 10⁻⁶ F

Frequency = 500 Hz

Now,

Impedance = \frac{1}{2\times\pi\times f\times C}

or

Impedance = \frac{1}{2\times\pi\times500\times5\times10^{-6}}

or

Impedance = 63.66 ohm

Part 2

Inductance = 60 mH = 60 × 10⁻³ H

Frequency = 500 Hz

Now,

Impedance for an inductor = 2πfL

thus,

Impedance = 2 × π × 500 × 60 × 10⁻³

= 188.49 ohm

4 0
3 years ago
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