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Sedbober [7]
3 years ago
10

Inspections may be_____ or limited to a specific area such as electrical or plumbing

Engineering
1 answer:
Nuetrik [128]3 years ago
4 0
A is the answer for the sentence
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The ratio of boys to girls in the class was 2 to 3. If there were 18 girls in the class, how many students were in the class
iren2701 [21]
37 students in the class
18 Girls and 19 Boys
4 0
3 years ago
A refrigerator operates on average for 10.0 hours an day. If the power rating is the refrigerator is 709 w how much electrical e
Varvara68 [4.7K]

Answer:

61257.6 kW per day

Explanation:

The rating of the refrigerator is given as : 709 w

This means the power consumption is 709 joules per second

The operating time is given as 10 hours.

Change hours to second as

1 hour = 3600 seconds

10 hours = 36000 seconds

Apply the rating as;

709 w = 1 s

?         = 36000 seconds

perform cross product to get;

709 * 36000= 25524000 w

25524000 = 25524kW

For a day, 24 hours will be;

25524 kW = 10 hours

?                 =24 hours

={24*25524}/10 = 61257.6 kW per day

6 0
3 years ago
An aluminum alloy tube with an outside diameter of 3.50 in. and a wall thickness of 0.30 in. is used as a 14 ft long column. Ass
slega [8]

Answer:

slenderness ratio = 147.8

buckling load = 13.62 kips

Explanation:

Given data:

outside diameter is 3.50 inc

wall thickness 0.30 inc

length of column is 14 ft

E = 10,000 ksi

moment of inertia = \frac{\pi}{64 (D_O^2 -D_i^2)}

I = \frac{\pi}{64}(3.5^2 -2.9^2) = 3.894 in^4

Area = \frac{\pi}{4} (3.5^2 -2.9^2) = 3.015 in^2

radius = \sqrt{\frac{I}{A}}

r = \sqrt{\frac{3.894}{3.015}

r = 1.136 in

slenderness ratio = \frac{L}{r}

                              = \frac{14 *12}{1.136} = 147.8

buckling load = P_cr = \frac{\pi^2 EI}}{l^2}

P_{cr} = \frac{\pi^2 *10,000*3.844}{( 14\times 12)^2}

P_{cr} = 13.62 kips

3 0
3 years ago
An automobile engine provides 632 Joules of work to push the pistons and generates 2203 Joules of heat that must be carried away
Ronch [10]

Answer:

The change in internal energy of the engine is -1,571 Joules.

Explanation:

Change in internal energy (∆U) = energy output (U2) - energy generated (U1)

U1 is the energy generated = 2203 Joules

U2 is the energy output = 632 Joules

Change in internal energy (∆U) = 632 - 2203 = -1,571 Joules

3 0
3 years ago
Read 2 more answers
If a bolt is broken off flush with a surface, and the bolt is large enough in diameter, then you may be able to use a small ____
mina [271]

Answer:

A is the answer

Explanation:

3 0
3 years ago
Read 2 more answers
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