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icang [17]
1 year ago
11

Which requires more work, increasing a car's speed from 0 mph to 30 mph or from 50 mph to 60 mph?

Physics
1 answer:
Gnom [1K]1 year ago
8 0

Increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.

<h3>What is work?</h3>

Work is a measure of energy expended in moving an object. It is calculated by multiplying the force by the distance.

According to this question, work is required to move a car from one position to another.

The distance moved from 0 - 30mph is more than that moved from 50 - 60mph, therefore, increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.

Learn more about work at: brainly.com/question/19382352

#SPJ1

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Which segments show changes of state that absorb heat? Check all that apply.
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Answer:

B-C

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Explanation:

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The seven sciences the study of kinesiology includes are: exercise physiology, exercise anatomy, biomechanics, exercise psycholo
Alex

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3 years ago
A cubic sample of a new kind of artificial tissue is subject to an increase in pressure of 160 kPa which results in a reduction
grin007 [14]

Answer:

0.82 MPa

Explanation:

the change in pressure 'σ'=160kPa

K= σ/∈Ф_v => σ/3∈Ф_L

K= 160/(3 x 0.065)

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3 0
2 years ago
A certain radio wave has a wavelength of 6.0 × 10-2m. What is its frequency in hertz?
rodikova [14]

Answer:

The frequency of the wave is 5 x 10⁹ Hz

Explanation:

Given;

wavelength of the radio wave, λ = 6.0 × 10⁻²m

radio wave is an example of electromagnetic wave, and electromagnetic waves travel with speed of light, which is equal to 3 x 10⁸ m/s².

Applying wave equation;

V = F λ

where;

V is the speed of the wave

F is the frequency of the wave

λ  is the wavelength

Make F the subject of the formula

F = V /  λ

F = (3 x 10⁸) / (6.0 × 10⁻²)

F = 5 x 10⁹ Hz

Therefore, the frequency of the wave is 5 x 10⁹ Hz

8 0
3 years ago
Does the galvanometer deflect to the left or the right when:________
igomit [66]

Complete question is;

Does the galvanometer deflect to the left or the right when

a) the magnet is being pushed in

b) the magnet is being pulled out

c) the magnet is being held steady?

Answer:

Option A - when the magnet is being pulled out

Explanation:

Faraday’s law of electromagnetic induction states that: “Voltage is induced in a circuit whenever relative motion exists between the conductor and the magnetic field, and the magnitude of the voltage will be proportional to the rate of change of the flux”.

Now, applying it to the question, When the magnet is moved towards the sensitive center of the galvanometer and then pulled out, the needle of the galvanometer will deflect away from its center position in one direction only but when it is held steady, the needle of the galvanometer will return back to zero.

7 0
3 years ago
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