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nataly862011 [7]
4 years ago
7

How many neutrons does an element have if its atomic number is 56 and its mass number is 152?

Chemistry
1 answer:
julsineya [31]4 years ago
3 0
It would have 56 protons so you have to subtract those from the mass number which is 152-56=96
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The burning point of water in Celsius or the cooling point?
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Escaping from the haunted house, Anna ran home immediately to her chemistry lab
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89.1% Au

The molar mass of Au2O3 is 2(196.97) + 3(16.00) = 441.94 g/mol
The mass percent of Au is therefore 2(196.97) / 441.94, which is 393.94/441.94 = 0.891 —> 89.1%
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Why is pure silicon a poor conductor at room temperature?
Georgia [21]
Because pure silicon is a perfect semiconductor.

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5 0
3 years ago
((2.0265-2.02)/2.0265) x 100.00
lianna [129]

Answer 0.5

when reporting calculations from sig figs, report the number of sig figs in the least accurate measurement

so

((2.0265-2.02)/2.0265) x 100.00

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0.5

3 0
3 years ago
Which isotope will spontaneously decay and emit particles with a charge of +2?
VikaD [51]

Answer: The correct option is 4.

Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:

1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

2) Beta-minus decay: It is a decay in which a beta particle is released. The  beta particle released has a mass number of 0 and a charge of (-1).

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0\beta

For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form _{25}^{53}\textrm{Mn}

_{26}^{53}\textrm{Fe}\rightarrow _{25}^{53}\textrm{Mn}+_{+1}^0\beta

Option 2: This nuclei will undergo beta-minus decay process to form _{80}^{198}\textrm{Hg}

_{79}^{198}\textrm{Au}\rightarrow _{80}^{198}\textrm{Hg}+_{-1}^0\beta

Option 3: This nuclei will undergo a beta minus decay process to form _{56}^{137}\textrm{Ba}

_{55}^{137}\textrm{Cs}\rightarrow _{56}^{137}\textrm{Ba}+_{-1}^0\beta

Option 4: This nuclei will undergo an alpha decay process to form _{85}^{216}\textrm{At}

_{87}^{220}\textrm{Fr}\rightarrow _{85}^{216}\textrm{At}+_2^4\alpha

Hence, the correct option is 4.

7 0
4 years ago
Read 2 more answers
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