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nataly862011 [7]
3 years ago
7

How many neutrons does an element have if its atomic number is 56 and its mass number is 152?

Chemistry
1 answer:
julsineya [31]3 years ago
3 0
It would have 56 protons so you have to subtract those from the mass number which is 152-56=96
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Which element will only gain one electron during a chemical reaction?
Gelneren [198K]

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Explanation:

Halogens are a group of non-metals located in the seventh group on the periodic table. The will only gain one electron during a chemical reaction.

  • Halogens have a seven electrons in their outermost shell.
  • To complete the number of electrons in this shell, they need to gain an additional electron.
  • One more electron makes the halogen similar to the corresponding noble gas which is very stable.
  • Halogens are very reactive groups of elements and are highly electronegative.
  • They have a high affinity for electrons.
  • These elements are fluorine, chlorine, bromine, iodine and Astatine.

learn more:

Halogens brainly.com/question/6324347

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7 0
3 years ago
How can You friend electrons, protons and neutrons in an element?
Charra [1.4K]
You cant its not really that possible there diffrent elements to gather them into one source would be difficult more than likely a scientific explanation would answer this based upon test and research
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What is the median of the following set: 2, 4, 6, 8, and 10?
labwork [276]

Answer:9

Explanation:

(3+8+10+15)/4 = 36/4 = 9

6 0
2 years ago
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Calculate the ph of a solution formed by mixing 200.0 ml of 0.30 m hclo with 300.0 ml of 0.20 m kclo. the ka for hclo is 2.9 × 1
velikii [3]
C(HClO) = 0,3 M.
<span>V(HClO) = 200 mL = 0,2 L.
n(HClO) = </span>c(HClO) · V(HClO).
n(HClO) = 0,06 mol.<span>
c(KClO</span>) = 0,2 M.
<span>V(KClO) = 0,3 L.
n(KClO) = 0,06 mol.
V(buffer solution) = 0,2 L + 0,3 L = 0,5 L.
ck</span>(HClO) = 0,06 mol ÷ 0,5 L = 0,12 M.
cs(KClO) = 0,06 mol ÷ 0,5 L = 0,12 M.<span>
Ka(HClO</span>) = 2,9·10⁻⁸.<span>
This is buffer solution, so use Henderson–Hasselbalch equation: 
pH = pKa + log(cs</span> ÷ ck).<span>
pH = -log(</span>2,9·10⁻⁸) + log(0,12 M ÷ 0,12 M).<span>
pH = 7,54 + 0.
pH = 7,54</span>
6 0
3 years ago
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