Answer: the final temperature of the steam 581.5 °C
Explanation:
Given that;
P₁ = 11 MPa
T₁ = 600°C
exit at; P₂= 5.5 MPa
Now from superheated steam table( p=11 MPa, T=600°C)
h₁ = 3615 kJ/kg
h₁ = h₂ ( by throttling process and adiabatic isentholpic )
from saturated steam table at; ( h= 3615 kJ/kg, P= 5.5 MPa )
Temperature = 581.5 °C
Therefore the final temperature of the steam 581.5 °C
Answer:
a. is correct.
Explanation:
During servicing you should examine each bearing carefully for chips, pits, and scratches, so Technician A is correct.
Discoloration of a bearingbis not acceptable wear, so Technician B is false.
Combine the answers: Only Technician A is correct therefore answer a. is the right answer.
Answer:
Depth of field = 347.619 nm
Explanation:
wavelenght = 365nm
N.A =0.63
k1= 0.6
so we have that the resolution limit is:
R=k1*A
R=0.6*365
R=219 nm
and the Depth of field needed for the best resolution is:
DoF = Resolution / N.A.
DoF= R/N.A
DoF= 219/0.63
DoF= 347.619 nm
Answer:
potato<-100
print(potato)
sqrt(potato)
potato<-potato*2
print(potato)
Explanation:
The complete question is as follows
Create a variable called potato whose value corresponds to the number of potatoes you’ve eaten in the last week. Or something equally ridiculous. Print out the value of potato.
Calculate the square root of potato using the sqrt() function. Print out the value of potato again to verify that the value of potato hasn’t changed.
Reassign the value of potato to potato * 2.
Print out the new value of potato to verify that it has changed
The question was answered using R programming language.
At line 1, I assumed that I ate 100 potatoes in the previous week.
So, potato = 100
At line 2, the value of potato is printed as 100.
At line 3, the square root of potato is calculated using sqrt function: Square for of 100 = 10
At line 4,the initial value of potato is doubled and stored in potato variable. 100 * 2 = 200
At line 5, the new value of potato is printed: 200.
Answer:
Volume of face centered cubic cell=
Explanation:
Consider the face centered cubic cell:
1 atom at each corner of cube.
1 atom at center of each face.
Consider the one face (ABCD) as shown in attachment for calculation:
Length of the all sides of face centered cubic cell is L.
Volume of face centered cubic cell= L^3
Now Consider the figure shown in attachment:
According to Pythagoras theorem on ΔADC.
(a is the atomic radius)
(Put in the formula of Volume)
Volume of face centered cubic cell= L^3
Volume of face centered cubic cell= 
Volume of face centered cubic cell= 
Volume of face centered cubic cell=
