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klio [65]
3 years ago
10

Technician A says that when the malfunction indicator light or service engine light is on you should retrieve the diagnostic tro

uble code and follow the manufacturers recommended procedure. Technician B says that all obd-ll monitors must have the enabled criteria achieved before a test is performed. Who is correct?
Engineering
1 answer:
sergiy2304 [10]3 years ago
8 0

Answer: A.

Explanation: Which of the following types of data helps a tech to determine the actual conditions under which a fault code is set? a test light. When it comes to troubleshooting an on-board diagnostic (OBD) code, the tech's best tools include all of these EXCEPT: ... original equipment manufacturer (OEM) diagnostic flow charts.

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4 years ago
What do you own that might not be manufactured?
horrorfan [7]

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A pet

Explanation:

Latin time I checked animals aren't made by people? I honestly don't know if this helps but I'm technically not wrong.

8 0
3 years ago
Since the engineering design process may take the engineer back to its beginning, the process is considered ________
Valentin [98]

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Cyclical

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3 years ago
A freezer is maintained at 20°F by removing heat from it at a rate of 75 Btu/min. The power input to the freezer is 0.70 hp, and
Igoryamba

Answer:

Explanation:

Cop of reversible refrigerator = TL / ( TH - TL)

TL = low temperature of freezer = 20 °F

TH = temperature of air around = 75 °F

Heat removal rate QL = 75 Btu/min

W actual, power input = 0.7 hp

conversion on F to kelvin = (T (°F) + 460 ) × 5 / 9

COP ( coefficient of performance) reversible = (20 + 460) × 5/9 / (5/9 ( ( 75 +460) - (20 + 460) ))

COP reversible = 480 / 55 = 8.73

irreversibility expression, I = W actual - W rev

COP r = QL / Wrev

W rev = QL /  COP r  where 75 Btu/min = 1.76856651 hp  where W actual = 0.70 hp

a) W rev =  1.76856651 hp  /  8.73  = 0.20258 hp is reversible power

I = W actual - W rev

b) I = 0.7 hp - 0.20258 hp = 0.4974 hp

c) the second-law efficiency of this freezer = W rev / W actual =  0.20258 hp / 0.7 hp = 0.2894 × 100 = 28.94 %

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4 years ago
Calculate the wavelength of the first line in the Lyman series and show this line in the ultraviolet part of the spectrum?​
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I am not noobqueen of the square footage

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