Answer: E-cycle used computer equipment. Recycle Printer Cartridges and Drum Units. Properly Dispose of Old Technology.
Hope this helps!
Answer:
volume = 53.747 m3 = 14198.138 gal
weight = 526652 N = 118396.08 lbf
Explanation:
We know that volume of water
![volume = A'\times H](https://tex.z-dn.net/?f=volume%20%20%3D%20%20A%27%5Ctimes%20H)
where A' = 61% of A
![= 0.61\times 2667 = 1626.87 sq ft](https://tex.z-dn.net/?f=%20%3D%200.61%5Ctimes%202667%20%3D%201626.87%20sq%20ft)
![volume = 1626.87 \times (\frac{14}{12} ft)](https://tex.z-dn.net/?f=volume%20%20%3D%20%201626.87%20%5Ctimes%20%28%5Cfrac%7B14%7D%7B12%7D%20ft%29)
=1898.015 ft^3
![in\ m^3 = \frac{ 1898.015}{35.315} = 53.7457 m^3](https://tex.z-dn.net/?f=in%5C%20m%5E3%20%3D%20%5Cfrac%7B%201898.015%7D%7B35.315%7D%20%3D%20%20%2053.7457%20m%5E3)
![in\ gallon = 1898.015 \times 7.481 = 14198.138 gallon](https://tex.z-dn.net/?f=in%5C%20gallon%20%3D%201898.015%20%5Ctimes%207.481%20%3D%2014198.138%20gallon)
![= 1000\times 53.74\times 9.8](https://tex.z-dn.net/?f=%3D%201000%5Ctimes%2053.74%5Ctimes%209.8)
=526652 N
![In\ lbf = \frac{526652}{4.448} = 118396.08 lbf](https://tex.z-dn.net/?f=In%5C%20lbf%20%3D%20%20%5Cfrac%7B526652%7D%7B4.448%7D%20%3D%20118396.08%20lbf)
Decolagem e pouso
espero que ajude
Answer:
a)
, b)
, c) ![T = 200.829\,^{\textdegree}F](https://tex.z-dn.net/?f=T%20%3D%20200.829%5C%2C%5E%7B%5Ctextdegree%7DF)
Explanation:
a) The tank can be modelled by the Principle of Mass Conservation:
![\dot m_{1} + \dot m_{2} - \dot m_{3} = 0](https://tex.z-dn.net/?f=%5Cdot%20m_%7B1%7D%20%2B%20%5Cdot%20m_%7B2%7D%20-%20%5Cdot%20m_%7B3%7D%20%3D%200)
The mass flow rate exiting the tank is:
![\dot m_{3} = \dot m_{1} + \dot m_{2}](https://tex.z-dn.net/?f=%5Cdot%20m_%7B3%7D%20%3D%20%5Cdot%20m_%7B1%7D%20%2B%20%5Cdot%20m_%7B2%7D)
![\dot m_{3} = 125\,\frac{lbm}{s} + 10\,\frac{lbm}{s}](https://tex.z-dn.net/?f=%5Cdot%20m_%7B3%7D%20%3D%20125%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%2B%2010%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D)
![\dot m_{3} = 135\,\frac{lbm}{s}](https://tex.z-dn.net/?f=%5Cdot%20m_%7B3%7D%20%3D%20135%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D)
b) An expression for the specific enthalpy at outlet is derived from the First Law of Thermodynamics:
![\dot m_{1}\cdot h_{1} + \dot m_{2} \cdot h_{2} - \dot m_{3}\cdot h_{3} = 0](https://tex.z-dn.net/?f=%5Cdot%20m_%7B1%7D%5Ccdot%20h_%7B1%7D%20%2B%20%5Cdot%20m_%7B2%7D%20%5Ccdot%20h_%7B2%7D%20-%20%5Cdot%20m_%7B3%7D%5Ccdot%20h_%7B3%7D%20%3D%200)
![h_{3} = \frac{\dot m_{1}\cdot h_{1}+\dot m_{2}\cdot h_{2}}{\dot m_{3}}](https://tex.z-dn.net/?f=h_%7B3%7D%20%3D%20%5Cfrac%7B%5Cdot%20m_%7B1%7D%5Ccdot%20h_%7B1%7D%2B%5Cdot%20m_%7B2%7D%5Ccdot%20h_%7B2%7D%7D%7B%5Cdot%20m_%7B3%7D%7D)
Properties of water are obtained from tables:
![h_{1}=180.16\,\frac{BTU}{lbm}](https://tex.z-dn.net/?f=h_%7B1%7D%3D180.16%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D)
![h_{2}=28.08\,\frac{BTU}{lbm} + \left(0.01604\,\frac{ft^{3}}{lbm}\right)\cdot (14.7\,psia-0.25638\,psia)](https://tex.z-dn.net/?f=h_%7B2%7D%3D28.08%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D%20%2B%20%5Cleft%280.01604%5C%2C%5Cfrac%7Bft%5E%7B3%7D%7D%7Blbm%7D%5Cright%29%5Ccdot%20%2814.7%5C%2Cpsia-0.25638%5C%2Cpsia%29)
![h_{2}=29.032\,\frac{BTU}{lbm}](https://tex.z-dn.net/?f=h_%7B2%7D%3D29.032%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D)
The specific enthalpy at outlet is:
![h_{3}=\frac{(125\,\frac{lbm}{s} )\cdot (180.16\,\frac{BTU}{lbm} )+(10\,\frac{lbm}{s} )\cdot (29.032\,\frac{BTU}{lbm} )}{135\,\frac{lbm}{s} }](https://tex.z-dn.net/?f=h_%7B3%7D%3D%5Cfrac%7B%28125%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%29%5Ccdot%20%28180.16%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D%20%29%2B%2810%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%29%5Ccdot%20%2829.032%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D%20%29%7D%7B135%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%7D)
![h_{3}=168.965\,\frac{BTU}{lbm}](https://tex.z-dn.net/?f=h_%7B3%7D%3D168.965%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D)
c) After a quick interpolation from data availables on water tables, the final temperature is:
![T = 200.829\,^{\textdegree}F](https://tex.z-dn.net/?f=T%20%3D%20200.829%5C%2C%5E%7B%5Ctextdegree%7DF)