Argue the importance to society of incorporating green building into an engineer’s designs, with at least two examples.

A hypothetical metal alloy has a grain diameter of 1.7 102 mm. After a heat treatment at 450C for 250 min, the grain diameter ha

Romashka-Z-Leto [24]

Answer:

the required time for the specimen is 1109.4 min

Explanation:

Given that;

diameter of metal alloy d₀ = 1.7 × 10² mm

Temperature of heat treatment T = 450°C = 450 + 273 = 723 K

Time period of heat treatment t = 250 min

Increased grain diameter 4.5 × 10² mm

grain diameter exponent n = 2.1

First we calculate the time independent constant K

dⁿ - d₀ⁿ = Kt

K = (dⁿ - d₀ⁿ) / t

we substitute

K = (( 4.5 × 10² )²'¹ - ( 1.7 × 10² )²'¹) / 250

K = (373032.163378 - 48299.511117) / 250

K = 1298.9306 mm²/min

Now, we calculate the time required for the specimen to achieve the given grain diameter ( 8.7 × 10² mm )

dⁿ - d₀ⁿ = Kt

t = (dⁿ - d₀ⁿ) / K

t = (( 8.7 × 10² )²'¹ - ( 1.7 × 10² )²'¹) / 1298.9306

t = ( 1489328.26061158 - 48299.511117) / 1298.9306

t = 1441028.74949458 / 1298.9306

t = 1109.4 min

Therefore, the required time for the specimen is 1109.4 min

4 0

3 years ago

A rectangular conductor with a cross sectional area of 1.04 square millimeters (mm) ^2 has a resistance of 0.075 ohms. What woul

kogti [31]

Answer:

0.0375 ohms

Explanation:

The resistance of a material is the product of the resistivity of the material by the length of the material divided by its cross-section area.

Mathematically,

resistance= resistivity × length/area

In this case the resistivity of the material is the same, and the length is the same thus, assume a length of 1 unit, the cross-section area is the one changing

In applying the formula,

resistivity is r and length is l=1 unit, find the resistivity the material as;

resistance= resistivity * length /area

0.075=r*1/1.04

0.075=r*0.9615

0.075/0.9615 =r

r=0.078

use the r=0.078 , a length of 1 unit (assumed), and area of 2.08 mm² to find the new resistance

Resistance= resistivity * length /area

Resistance = 0.078*1/2.08

Resistance= 0.078 * 0.4807 = 0.0375 ohms

Point to note here is that the greater the cross-section area, the less the resistance.

4 0

3 years ago

Water flows through a pipe of 100 mm at the rate of 0.9 m3 per minute at section A. It tapers to 50mm diameter at B, A being 1.5

pochemuha

Answer:

The velocities in points A and B are 1.9 and 7.63 m/s respectively. The Pressure at point B is 28 Kpa.

Explanation:

Assuming the fluid to be incompressible we can apply for the continuity equation for fluids:

$Aa.Va=Ab.Vb=Q$

Where A, V and Q are the areas, velocities and volume rate respectively. For section A and B the areas are:

$Aa=\frac{pi.Da^2}{4}= \frac{\pi.(0.1m)^2}{4}=7.85*10^{-3}\ m^3$

$Ab=\frac{pi.Db^2}{4}= \frac{\pi.(0.05m)^2}{4}=1.95*10^{-3}\ m^3$

Using the volume rate:

$Va=\frac{Q}{Aa}=\frac{0.9m^3}{7.85*10^{-3}\ m^3} = 1.9\ m/s$

$Vb = \frac{Q}{Ab}= \frac{0.9m^3}{1.96*10^{-3}\ m^3} = 7.63\ m/s$

Assuming no losses, the energy equation for fluids can be written as:

$Pa+\frac{1}{2}pa.Va^2+pa.g.za=Pb+\frac{1}{2}pb.Vb^2+pb.g.zb$

Here P, V, p, z and g represent the pressure, velocities, height and gravity acceleration. Considering the zero height level at point A and solving for Pb:

$Pb=Pa+\frac{1}{2}pa(Va^2-Vb^2)-pa.g.za$

Knowing the manometric pressure in point A of 70kPa, the height at point B of 1.5 meters, the density of water of 1000 kg/m^3 and the velocities calculated, the pressure at B results:

$Pb = 70000Pa+ \frac{1}{2}*1000\ \frac{kg}{m^3}*((1.9m/s)^2 - (7.63m/s)^2) - 1000\frac{kg}{m^3}*9,81\frac{m}{s^2}*1.5m$

$Pb = 70000\ Pa-27303\ Pa - 14715\ Pa$

$Pb = 27,996\ Pa = 28\ kPa$

6 0

3 years ago

Technician A says that TSBs are typically updates to the owner's manual. Technician B says that TSBs are generally

vichka [17]

Answer:

Technician A says that TSBs are typically updates to the owner's manual. Technician B says that TSBs are generally

updated information on model changes that do not affect the technician. Who is correct? the answer is c

4 0

3 years ago

Computers work with only two states: zero and one (e.g. short , tall)and is known as binary however in fuzzy logic there are ran

Ymorist [56]

Answer:

1) a)True

b) False

2) False

2. True

4. True

5. True

Explanation:

1.a)Computers work with only two states: zero and one which is true, the language is in 1 and 0 which is called binary

b)in fuzzy logic there are range of states such as short, little tall, very tall etc...

That is false because Fuzzy logic contains also ones and zeros (Binary).

2)2. This is false because by combining the three colors we will get only

256*256*256 color and we don't get billions of colors

eg:R G B

255 0 0 -->one color

220 0 200---> one color

Due to the difficult economic times, increased global competition, demand for customization, and increased consumer sophistication, many companies have increased their investment in hiring many employees, and outsource & off shore middle managers True or False

yes this may be True because By increased global competition, demand for customization the product needs to be developed. And for development of new products we need employees, managers etc. This in-turn increases the outsourcing of offshore middle managers.

A mouse driver (software) can have a virus if its program gets infected true or False

This is True

It depends on the virus file. Some program need to be execute perfectly if it can be infected with virus. Some applications need not run because of virus files both the situations are possible.

5)Many managers were able to tackle y2k on time and saved billions. true or False;

This is True. After the year 2000, a lot of managers are able to control billions of people because many of the Top MNC's are tackled more by managers.

5 0

4 years ago