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topjm [15]
3 years ago
13

The temperature at 8:00

Physics
1 answer:
musickatia [10]3 years ago
6 0
Change in temperature = final temperature - Initial temperature 
Δt = t₂ - t₁
Δt = 17 - (-6)
Δt = 17 + 6 = 23 f

In short, Your Answer would be Option D

Hope this helps!
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A bird flew 16 km west in 5 hours , then flew 20 km east in 6 hours . What was the birds velocity?
LenaWriter [7]
During that period of time, the bird's displacement was 4 km east. So its velocity was (4km east)/(11hrs). That's 0.36 km/hour east. (rounded)
5 0
3 years ago
What is the restoring force of a pendulum
salantis [7]

Answer:

the Restoring force causes the vibrating object to go slower going further from the equilibrium position and to go faster as it approaches the equilibrium position. the restoring force is what is causing the vibration The tension force comes from the string tugging on the bob of the pendulum.

Explanation:

3 0
3 years ago
When carbon bonds with oxygen,
Ierofanga [76]

Answer:

Carbon dioxide

Explination:

I remember it from biology.

I hope this helps ^-^

6 0
3 years ago
While flying at an altitude of 5.75 km, you look out the window at various objects on the ground. If your ability to distinguish
Bingel [31]

Answer:

the smallest separation between two objects is 0.8067 m

Explanation:

Given the data in the question;

Altitude h = 5.75 km = 5750 m

Diameter D = 4.0 mm = 0.004 m

λ = 460 nm = 4.6 × 10⁻⁷ m

Now, Using Rayleigh criterion for Airy disks resolution.

we know that, Minimum angular separation for resolving two points is;

θ = 1.22λ / D

so we substitute

θ = (1.22 × 4.6 × 10⁻⁷)  / 0.004

θ = 5.612 × 10⁻⁷ / 0.004

θ = 1.403 × 10⁻⁴ rad  

so minimum separation d_{min =  θh

so we substitute

d_{min = (1.403 × 10⁻⁴) × 5750 m

d_{min = 0.8067 m

Therefore, the smallest separation between two objects is 0.8067 m

6 0
3 years ago
The legend that Benjamin Franklin flew a kite as a storm approached is only a legend; he was neither stupid nor suicidal. Suppos
UNO [17]

Answer:

The current on the water layer = 1.64×10^-3A

Explanation:

Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:

I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)

I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)

I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566

I = 252.83 -(4.623×10^-6)/ 154566

I = 252.83/154566

I = 1.64× 10^-3A

3 0
3 years ago
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