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abruzzese [7]
3 years ago
8

Convert 278000 into scientific notation

Physics
2 answers:
nirvana33 [79]3 years ago
8 0

2.78 X 10^5 is the best answer to be responded to

AnnZ [28]3 years ago
3 0

278000 written in scientific notation would be 2.78×10⁵.

You can convert the number into scientific notation by doing the following:

1. Turn 278000 into 2.78000.

2. Move the decimal point to the end of the number, so that it becomes 278000 again.

3. Count the number of places that the decimal point was moved.

Since the decimal point was moved 5 places to the right, the exponent on the 10 will be positive five. Therefore, 278000 becomes 2.78×10⁵.

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An environmentally-conscious student is breaking the rings from a six-pack drink holder before disposing of it. This reduces the
katrin2010 [14]

Answer: seen below.

Explanation:

Firstly we need to remember what exothermic reaction is in thermodynamics. exothermic reaction describes a process or reaction that releases energy from the system to its surroundings, usually in the form of heat, but also in a form of light, sound, or electricity.

In this scenario, due to the heating up nature noticed by the ring during breaking shows that energy is being released to the surrounding in the form of heat which suggest it being an exothermic reaction.

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3 years ago
g You heard the sound of a distant explosion (3.50 A/10) seconds after you saw it happen. If the temperature of the air is (15.0
Soloha48 [4]

Answer:

The answer is "1557 meters".

Explanation:

speed of sound in (\frac{m}{s}) = 331.5 + 0.60 \ T^{\circ}\ C\\\\

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8 0
3 years ago
The New England Merchants Bank Building in Boston is 152 mm high. On windy days it sways with a frequency of 0.20 HzHz , and the
kkurt [141]

Answer:

The total distance, side to side, that the top of the building moves during such an oscillation = 31 cm

Explanation:

Let the total side to side motion be 2A. Where A is maximum acceleration.

Now, we know know that equation for maximum acceleration is;

A = α(max) / [(2πf)^(2)]

So 2A = 2[α(max) / [(2πf)^(2)] ]

α(max) = (0.025 x 9.81) while frequency(f) from the question is 0.2Hz.

Therefore 2A = 2 [(0.025 x 9.81) / [((2π(0.2)) ^(2)] ] = 2( 0.245 / 1.58) = 0.31m or 31cm

3 0
3 years ago
An object is placed a great distance from a concave (converging) mirror. Where will light from the object be collected?
AveGali [126]

Answer: at the center of curvature of the mirror on the same side of the mirror as the object

A concave mirror has a reflective surface that is curved inwards.  This type of mirrors reflects the light making it converge in a focal point, therefore they are used to focus the light.

This occurs because the light is reflected with different angles, since the normal to the surface varies from one point to another of the mirror.

Nevertheless, it is important to note the object must be within the radius of curvature of the mirror.

In addition, it is important to state clear the following:

-If the object is at a distance greater than the focal distance, a <u>real</u> and <u>inverted image</u> is formed that may be greater or less than the object.

-If the object is at a distance smaller than the focal distance, a <u>virtual</u> image is formed, <u>right and larger than the object</u>.

In this case the object is placed a great distance (it can be said at infinite) from the concave mirror, hence the image formed will be real, inverted and smaller than the object.

When we say <u>real</u>, it means the image is formed in the same side of the mirror as the object and the image can be seen on a screen.

5 0
3 years ago
Read 2 more answers
The block exerts a force F on the dart that is proportional to the dart’s velocity v and in the opposite direction, that is F =
Natali5045456 [20]

Answer:

s = mV/2b

Assumptions: 1. the darts finally velocity is zero

2. The force being exerted on the dart by the block is constant and so the dart moves through the block with constant acceleration in the opposite direction. (Newton's second law)

3. Since the acceleration of the dart through the block is constant, then the equations of constant acceleration motion apply to the motion of the dart through the block.

Explanation:

Let a = acceleration of the dart through the block

V = velocity of the dart

m = mass of the dart

Vf = finally velocity of the dart

S = distance traveled by the dart through the block.

From Newton's second law of motion which states that the acceleration of a body is in the same direction as the net force acting on the body and is equal to the force divided by the mass. That is F = ma

Also F = -bv ........(1)

Therefore -bv = ma........(2)

From the equals of constant acceleration motion, Vf² = V² + 2aS

Vf = 0

0² = V² + 2aS

-2aS = V²

a = -V² / 2S

Substituting this expression for a in

Equation (2) above

-bV = m( - V²/2S)

On rearranging,

S = mV/2b

6 0
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