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Tatiana [17]
2 years ago
9

Which starting material is the limiting reagent in this procedure? which reagent is used in excess? how great is the molar exces

s (how many times greater)?
Physics
1 answer:
alexandr1967 [171]2 years ago
7 0

The limiting reagent in this procedure is the substance that is completely used in the reaction. The substance which is not completely used is called excess.

The beginning cloth in a chemical reaction is known as the reactant. each chemical response could have one or more reactants.

In a chemical response limiting reagent is the reactant this is fed on first and prevents any similar reaction from happening. the quantity of product shaped during the response is decided by means of the limiting reagent. as an example, allow us to recall the response of solution and chlorine

Materials used during the manufacture of the lively substance (e.g., tradition media, growth factors, and so on) and that are not meant to form a part of the active substance shall be taken into consideration as raw substances. cloth forming a critical part of the lively materials element shall be considered as the beginning substance.

Learn more about limiting reagents here:-brainly.com/question/26905271

#SPJ4

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Answer:

Gpe = 15680 Joules

Explanation:

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

Mass = 20 kg

Height = 80 m

We know that acceleration due to gravity is equal to 9.8 m/s²

To find the gravitational potential energy;

Gpe = mgh

Gpe = 20 * 80 * 9.8

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find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​
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Answer:

0.02

Explanation:

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Substituting F with 2 N, m with 10 kg and g with 9.81 then

\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02

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