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3 years ago

ASAP PLEASE HELP How does Earth's core transmit heat?

Physics

1 answer:

beks73 [17]3 years ago

6 0

Answer:

There are three main sources of heat in the deep earth:

(1) heat from when the planet formed and accreted, which has not yet been lost;

(2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elements.

Explanation:

hope it was helpful...

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A 61.6 turns circular coil with radius 4.44 cm and resistance 2.34 Ω is placed in a magnetic field directed perpendicular to the

Setler [38]

Answer:

Induced emf is 0.324 V

Explanation:

We have,

Number of turns, n = 61.6

Radius of circular coil, r = 4.44 cm

Resistance of coil, R = 2.34 Ω

The magnitude of the magnetic field varies in time according to the expression :

$B=a_1t+a_2t^2$

$a_1=0.0411\\\\a_2=0.044$

The magnitude of the induced emf in the coil is given by :

$\epsilon=\dfrac{d\phi}{dt}\\\\\epsilon=\dfrac{d(NBA)}{dt}\\\\\epsilon=NA\dfrac{dB}{dt}$

$\epsilon=\pi r^2\dfrac{dB}{dt}$

At t = 9.21 s,

$\dfrac{dB}{dt}=(0.0411+2\times 0.044 \times 9.21)\\\\\dfrac{dB}{dt}=0.851\ T/s$

$\epsilon=61.6\times \pi \times (4.44 \times 10^{-2})^2\times 0.851$

$\epsilon=5.27\times 10^{-3}\ V$

So, the magnitude of the induced emf in the coil is 0.324 V

5 0

4 years ago

A_____ is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree celsius.

Rom4ik [11]

<span>A_____ is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree celsius.

Specific Heat Capacity of Water.
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5 0

4 years ago

Read 2 more answers

A vertical spring with a spring constant of 310 N/m is mounted on the floor. From directly above the spring, which is unstrained

EleoNora [17]

Answer:

7.3cm above the compressed spring.

Explanation:

We can use the conservation energy theorem to solve this problem:

$U_{1}+K_1=U_e+U_2+K_2\\m*g*h+0=\frac{1}{2}k*x^2+0+0\\\\h=\frac{k*x^2}{2*m*g}\\\\h=\frac{310N/m*(3.6*10^{-2})^2}{2*0.28kg*9.8m/s^2}\\\\h=0.073m$

The block was dropped 7.3cm above the compressed spring.

8 0

3 years ago

A rope attached to a load of 175 kg bricks Ilifts the bricks with a steady acceleration of 0.12.m/s^2 straight up. What is the t

andrew-mc [135]

Answer:

Tension, T = 1736 N

Explanation:

It is given that,

Mass of bricks, m = 175 kg

A rope is attached to a load of 175 kg bricks lifts the bricks with a steady acceleration of 0.12 m/s² in vertically upwards direction. let T is the tension in the rope. Using second equation of motion as :

T - mg = ma

T = ma + mg

T = m(a + g)

T = 175 kg ( 0.12 m/s² + 9.8 m/s² )

T = 1736 N

Hence, the tension in the wire is 1736 N.

4 0

3 years ago

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The 60-mm-diameter shaft is made of 6061-T6 aluminum having an allowable shear stress of τallow = 80 MPa. Determine the maximum

grin007 [14]

The maximum allowable torque must correspond to the allowable shear stress for maximization. To solve this, we use the torsion formula:

Max. Allowable Shear Stress = Maximum Torque ÷ Cross-Sectional Area
8 x 10^6 Pa = Maximum Torque ÷ pi*(d/2)²
Maximum Torque = 8 x 10^6 Pa * pi*(0.06/2)² m²
Maximum Torque = 22,619.47 J or
Maximum Torque = 22.62 kJ

As for the second question, I have no reference figure so I am unable to answer it. I hope I was still able to help you, though.

5 0

4 years ago