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Natali [406]
3 years ago
13

The magnetic field at the equator points north. if you throw a positively charged object (for example, a baseball with some elec

trons removed) to the east, what is the direction of the magnetic force on the object
Physics
1 answer:
asambeis [7]3 years ago
7 0
Recall the equation for magnetic force:

F = qv x B          *x is cross product, not separate variable!

If the magnetic field points towards N and you throw E, then the magnetic force would point up, or out of the page. Use the right-hand rule. You point your finger towards the direction of the object, and curl your finger to the magnetic field. Your thumb is the direction of the magnetic force.

Hope this helps!
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You place a 0.17 kg can of soup and a 0.31 kg jar of pickles on the kitchen counter, separated by a distance of 0.42 m. What is
tangare [24]

1.984 \times 10^{-11} \mathrm{N} \text { is the force of gravity exerted on the jar of pickles. }

<u>Explanation</u>:

According to Newton's third law that each force has an equal and opposite reaction force in this case both of the jars will exert the same force an each other

. The force is given by

\mathrm{F}=\frac{G \times M_{1} \times M_{2}}{r^{2}}

Where, F = force, G=\text { gravitational constant }=\left(6.67 \times 10^{-11}\right), mass \left(\mathrm{M}_{1}\right)=0.17 \mathrm{kg}, mass \left M_{2}= 0.31 \mathrm{kg} and Distance(r) = 0.42 m.

Substitute the values in the formula.

\mathrm{F}=\frac{6.67 \times 10^{-11} \times 0.17 \times 0.31}{0.42^{2}}

\mathrm{F}=\frac{3.51 \times 10^{-12}}{0.176}

\mathrm{F}=1.984 \times 10^{-11} \mathrm{N}

\text { The force of gravity exerted on the jar of pickles is } 1.984 \times 10^{-11} \mathrm{N} \text { . }

3 0
3 years ago
a specimen of oil having an initial volume of 5000cm³ is subjected to a pressure of 10⁴N/m² and the volume decreases by 0.20cm³.
inessss [21]

Answer:

 B = 2.5 10⁸ Pa

Explanation:

The volume modulus is defined by

           B = - \frac{P}{ \frac{\Delta V}{V} }

           

The negative fate is for the module to be positive since the volume change is negative

       

It is not necessary to reduce the volumes to the SI system, since they are both in the same units

             B = - \frac{10^4}{ \frac{-0.20}{5000} } = \frac{10^4}{4 \ 10^{-5} }

             B = 2.5 10⁸ Pa

4 0
3 years ago
Can someone please help? Thank u!
Snowcat [4.5K]

Answer:

B. 7.5 m/s^2

Explanation:

To find acceleration you need to subtract the final velocity by the starting velocity then divide that by the time

a= v-v/t

a= 60-0/8

a= 60/8

a=7.5 m/s^2

7 0
2 years ago
A mercury thermometer has a glass bulb of interior volume 0.100 cm3 at 10°c. the glass capillary 10) tube above the bulb has an
Nadya [2.5K]
Initial volume of mercury is
V = 0.1 cm³

The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.

Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is 
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³

The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
   = (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
   = 4.5 cm

Answer: 4.5 cm
7 0
3 years ago
Read 2 more answers
A published hypothesis:
kow [346]

Answer:

should be tested by the scientific community

4 0
3 years ago
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