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Savatey [412]
3 years ago
11

A hockey puck is traveling to the left with a velocity of v=10 when it is struck by the hockey stick

Physics
1 answer:
Lera25 [3.4K]3 years ago
4 0
We have to calculate the impulse of a hockey puck.
Imp = m * ( v 1 - v 2 ) = m * Δ v
v 1 = - 10 i m/s,
v 2 = ( 20 * cos 40° ) i + ( 20 * sin 40° ) j =
= ( 20 * 0.766 ) i + ( 20 * 0.64278 ) j = ( 15.32 i + 12.855 j ) m/s
Δ v = ( 15.32 i + 12.855 j ) - ( - 10 i ) =
= 15.32 i + 12.855 j + 10 i = 25.32 i + 12.855 j
| Δv | = √ ( 25.32² + 12.855²) = √806.35 = 28.4 m/s
Imp = 0.2 kg * 28.4 m/s = 5.68 N-s
Answer: D ) 5.68 N-s. 
 
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if for every force there is an equal and opposite reaction force, how is it possible for an object to accelerate
lesya692 [45]

Answer:

By the use of the reaction force one body is able to accelerate because it is not fixed to a rigid support which offers a materialistic resistance.

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For every  force there is an equal and opposite reaction is stated in the Newton's third law of motion holds true universally.

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8 0
3 years ago
A bike race against the clock takes place on a straight road. Yan drives at 37 km / h and he starts the course 30s before Christ
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Given data:

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u_1=37\text{ km/h}

Christopher speed;

u_2=38.9\text{ km/h}

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Part (A)

The distance is given as,

d=ut

Let both Yan and Christophe meet at d distance from the start position. Therefore,

u_1t=u_2(t-30)

Substituting all known values,

\begin{gathered} (37\text{ km/h})t=(38.9\text{ km/h})\times(t-30) \\ \frac{(37\text{ km/h})}{(38.9\text{ km/h})}=\frac{(t-30)}{t} \\ 0.95=1-\frac{30}{t} \\ \frac{30}{t}=1-0.95 \\ \frac{30}{t}=0.05 \\ t=\frac{30}{0.05} \\ t=600\text{ s} \end{gathered}

Therefore, 600 s after Yan's departure Christophe will join him.

Part (B)

The distance is given as,

d=u_1t

Substituting all known values,

\begin{gathered} d=(37\text{ km/h})\times(600\text{ s}) \\ =(37\text{ km/h})\times(600\text{ s})\times(\frac{1\text{ hr}}{3600\text{ s}}) \\ \approx6.17\text{ km} \end{gathered}

Therefore, Christophe joins Yan after 6.17 km from the start.

3 0
1 year ago
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Gwar [14]

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3 0
2 years ago
A current of 2.35 A flows through a 1.11 mm diameter copper wire that is connected to a capacitor plate. The current is directed
antoniya [11.8K]

Answer:

charge flowing in the copper wire is 2.585\times 10^{-3}C

Explanation:

We have given current i = 2.35 A

Time through which charge is charge is transferred t=1.10\times 10^{-3}sec

We have to find the charge flowing in this time

We know that charge is given by Q = i×t , here i is current and t is time

So charge = Q=1.1\times 10^{-3}\times 2.35=2.585\times 10^{-3}C

So charge flowing in the copper wire is 2.585\times 10^{-3}C

6 0
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