It is orbiting the object.
Answer:
6.65m/s
Explanation:
Using the equation of motion
S = ut + 1/2gt²
S is the height of fall
t is the time
u is the horizontal velocity
g is the acceleration due to gravity
Given
S = 300 + 50
S = 350m
t = 7.8seconds
g = 9.8m/s^2
Get S
S = 7.8u + 1/2(9.8)(7.8)²
S = 7.8u + 298.116
350 = 7.8u + 298.116
7.8u = 350 - 298.116
7.8u = 51.884
u = 51.884/7.8
u = 6.65m/s
Hence the rock's horizontal velocity was 6.65m/s
Answer:
Cannonball b spends more time in the air than cannonball a.
Explanation:
Starting with the definition of acceleration, we have that:

Since both cannonballs will stop in their maximum height, their final velocity is zero. And since the acceleration in the y-axis is g, we have:

Now, this time interval is from the moment the cannonballs are launched to the moment of their maximum height, exactly the half of their time in the air. So their flying time t_f is (the minus sign is ignored since we are interested in the magnitudes only):

Then, we can see that the time the cannonballs spend in the air is proportional to the vertical component of the initial velocity. And we know that:

Finally, since
and
, we can conclude that:

In words, the cannonball b spends more time in the air than cannonball a.
Answer:
False
Explanation:
ac = v^2/r
acceleration is not dependent on the mass of the orbiting object.
Answer:
2 revolutions
Explanation:
Assume that when she runs off the edge of the 8.3m high cliff, her vertical speed is 0. So gravitational acceleration g = 9.8m/s2 is the only thing that makes her fall down. So we can use the following equation of motion to calculate the time it takes for her to fall down:

where s = 8.3 m is the distance that she falls, t is the time it takes to fall, which is what we are looking for


Since she rotates with an average angular speed of 1.6rev/s. The number of revolutions she would make within 1.3s is
