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viktelen [127]
2 years ago
11

A 16.9 kg monkey is swinging on a

Physics
1 answer:
mrs_skeptik [129]2 years ago
5 0

The potential energy of the monkey at the given position is 600.9 J.

<h3>What is potential energy?</h3>

Potential energy is the energy stored in a body that depends upon the relative position of various parts of the body.

It increases with increase in the height of the object above the ground level.

<h3>Potential energy of the monkey</h3>

The potential energy of the monkey is calculated as follows;

P.E = mgh

P.E = mg (L sin43)

where;

  • m is mass of the monkey, given as 16.9 kg
  • g is acceleration due to gravity, given as 9.8 m/s²
  • L is length of the vine given as 5.32 m

Substitute the given parameters and solve potential energy of the monkey

P.E = (16.9)(9.8)( 5.32 x sin 43)

P.E = 600.9 J

Thus, the potential energy of the monkey at the given position is 600.9 J.

Learn more about potential energy here: brainly.com/question/1242059

#SPJ1

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Average speed = (S - 1) + (S + 1) / 2
= S

S = 6 miles / 4 hours
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4 0
3 years ago
In a thunder and lightning storm there is a rule of thumb that many people follow. After seeing the lightning, count seconds to
lubasha [3.4K]

Answer:

2.837% less than actual value.

Explanation:

Based on given information let's calculate our value.

S = Vxt = 331m/s x 5s = 1655m, that is the total distance that sound would travel in 5 seconds.

1mile = 1609.34meters.

percentage error is.

\frac{actual-calculated}{actual} *100 = \frac{1609.34-1655}{1609.34} *100 = -2.83%

negative indicates less than actual value.

3 0
4 years ago
What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters
Volgvan
A_central = v^2/r = (19)^2/10 = 36.1 m/s^2
7 0
3 years ago
Read 2 more answers
6. A 4 kg object hangs below a 6 kg object by a string of negligible mass. If the 6 kg object is pulled upward by a force of 440
MrRissso [65]

Answer:

T =176 N

Explanation:

from diagram

F -(m_1+m_2_g) = (m_1+m_2_g)a

440 - (6+4)g = (6+4)a

a =\frac{440-10*9.8}{10}

a =34.2 m/s^2

frrom free body diagram of mass m2 = 4kg

T -m_2g =m_2a

T = m_2(g +a)

T = 4(9.81+34.2)

T =176 N

7 0
4 years ago
The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 8.9 km. Assume the
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Answer:

\frac{I}{I_0}=113.68

Explanation:

P = Acoustic power = 63 µW

r = Distance to the sound source = 210 m

Acoustic power

P=IA\\\Rightarrow I=\frac{P}{A}\\\Rightarrow I=\frac{63\times 10^{-6}}{4\times \pi \times 210^2}

Threshold intensity = I_0=1\times 10^{-12}\ W/m^2

Ratio

\frac{I}{I_0}=\frac{\frac{63\times 10^{-6}}{4\times \pi \times 210^2}}{1\times 10^{-12}}\\\Rightarrow \frac{I}{I_0}=113.68

Ratio of the acoustic intensity produced by the juvenile howler to the reference intensity is 113.68

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3 years ago
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