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Lerok [7]
2 years ago
15

If an object is placed between a convex lens and its focal point, which type of image will be produced?

Physics
2 answers:
Andreas93 [3]2 years ago
8 0
<span>virtual, upright, and magnified</span>
Nastasia [14]2 years ago
4 0

Answer:

virtual, upright and magnified

Explanation:

As we know by lens formula

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

now we know that

d_o < f

now we have

\frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o}

now we have

d_i = -\frac{d_o f}{f - d_o}

now the magnification is given as

m = \frac{d_i}{d_o}

m = -\frac{f}{f - d_o}

Since here magnification is negative

so image is virtual and upright

also we can see from equation

m > 1

so here we have

virtual, upright and magnified

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Answer: wheel and axle

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4. X-ray radiation from diffraction and fluorescence instruments is a) Not very dangerous because the X-rays are absorbed in the
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c) Very dangerous and users must not override devices designed to protect from exposures.

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X-ray is a form of high energy electromagnetic radiation and are part of the electromagnetic spectrum.

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Hence, users must not override devices designed to protect from exposures. The best shielding device to protect one from exposure is Lead.

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A hockey puck is sliding across a frozen pond with an initial speed of 9.3 m/s. It comes to rest after sliding a distance of 42.
kondaur [170]

Answer:

The coefficient of kinetic friction between the puck and the ice is 0.11

Explanation:

Given;

initial speed, u = 9.3 m/s

sliding distance, S = 42 m

From equation of motion we determine the acceleration;

v² = u² + 2as

0 = (9.3)² + (2x42)a

- 84a = 86.49

a = -86.49/84

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F_k = \mu_k N = ma

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μk is the coefficient of kinetic friction

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μk = 0.11

Therefore, the coefficient of kinetic friction between the puck and the ice is 0.11

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