Question

If an object is placed between a convex lens and its focal point, which type of image will be produced?

Answer 1

virtual, upright, and magnified

Answer 2

Answer:

virtual, upright and magnified

Explanation:

As we know by lens formula

$\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}$

now we know that

$d_o < f$

now we have

$\frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o}$

now we have

$d_i = -\frac{d_o f}{f - d_o}$

now the magnification is given as

$m = \frac{d_i}{d_o}$

$m = -\frac{f}{f - d_o}$

Since here magnification is negative

so image is virtual and upright

also we can see from equation

m > 1

so here we have

virtual, upright and magnified