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omeli [17]
2 years ago
12

No question................................

Chemistry
1 answer:
mihalych1998 [28]2 years ago
5 0

Answer:

ok  

Explanation:

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In the 18th century, Italian biologist Lazzaro Spallanzani designed an experiment supporting the hypothesis that gastric juices
AURORKA [14]

Stomach ulcers, I've read it online and I take the test

7 0
2 years ago
Read 2 more answers
At a certain temperature, Kc = 0.0500 and ∆H = +39.0 kJ for the reaction below, 2 MgCl2(s) + O2(g) → 2MgO(s) + Cl2(g) Calculate
Minchanka [31]

Explanation:

Since, it is shown that the reaction has been reversed. Therefore, value of K_{c} will become \frac{1}{K_{c}}.

Hence, new K_{c'} = \frac{1}{K_{c}}

                                      = \frac{1}{0.0500}

                                      = 20

Also, the number of moles of each reactant has been halved. So, K_{c''} for the reaction MgO(s) + \frac{1}{2}Cl2(g) → MgCl_{2}(s) + \frac{1}{2} O2(g) will also get halved.

Therefore,     K_{c''}  = K_{c'} = (20)^{0.5}

                               = 4.47

As the value of \Delta H is given as +39.0 kJ. So, it means that the reaction is endothermic in nature. So, energy of reactants will be more than the products. Hence, according to Le Chatelier's principle reaction will move in the forward direction.

As a result, K_{c} will also increase with increase in temperature.

6 0
3 years ago
Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o
vivado [14]

<u>Answer:</u>

<u>For 1:</u> The amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

<u>For 2:</u> The amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

<u>Explanation:</u>

  • <u>For 1:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}

Molarity of KIO_3 solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol

Hence, the amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

  • <u>For 2:</u>

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = \frac{1}{2}\times 0.00025=0.000125mol of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

6 0
3 years ago
What is the pH of a solution with [H+]=6.2x10-9 M?
Serga [27]

Answer: 8.2

Explanation:

pH of a solution is  - Log [ H+].

pH = - Log [ 6.2 x 10-9 M]

     = 9 - 0.7924

pH =  8.24 approx 8.2

3 0
3 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 7.80 moles of magnesium perchlorate, Mg(ClO4)2.
Dmitry [639]
 The number of moles of moles of  Magnesium,chlorine and oxygen atoms in 7.80 moles of Mg(ClO4)2 is calculated as below

find the total number of each atom in Mg(ClO4)2

that is mg = 1 atom
        Cl =  1x2 = 2 atoms
        O  = 4  x2 = 8 atoms

then multiply 7.80 moles with total number of each atom , to get the number moles of each atom
that is

Mg = 7.80 x1= 7.80  moles
cl =   7.80  x2=15.6  moles
O =  7.80 x8= 62.4 moles

5 0
3 years ago
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