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Advocard [28]
3 years ago
7

A rock is dropped from a cliff and hits the ground 6.0 seconds later. How high is the cliff?

Physics
2 answers:
PolarNik [594]3 years ago
6 0
It all depends on the wight of the rock to but each 1 sec is 1 mile so about 6 miles
Lemur [1.5K]3 years ago
5 0

Answer:

The height of the cliff is found to be 176.4 m

Explanation:

Since, the body is being dropped from a certain height and reaches the ground in some time. Thus, we can apply the equations of motion (modified for vertical motion) in this case, due to constant accelerated motion. We have the following data:

Acceleration due to gravity = g = 9.8 m/s²

Time to reach ground = t = 6 sec

Initial Velocity of the Rock = Vi = 0 m/s (Because, the rock will be at rest, initially)

Height of cliff = H = ?

Now, applying second equation of motion (modified for vertical motion), to the rock, between the top of the cliff and ground, we get:

H = Vi t + (1/2)gt²

Using values:

H = (0 m/s)(6 sec) + (1/2)(9.8 m/s²)(6 sec)²

<u>H = 176.4 m</u>

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6 0
3 years ago
A current exists whenever electric charges move. If ΔQ is the net charge that passes through a surface during a time period Δt,
jeka57 [31]

Answer:

It represents the change in charge Q from time t = a to t = b

Explanation:

As given in the question the current is defined as the derivative of charge.

                                  I(t) = dQ(t)/dt ..... (i)

But if we take the inegral of the equation (i) for the time interval  from t=a to

t =b we get

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which shows the change in charge Q from time t = a to t = b. Form here we can say that, change in charge is defiend as the integral of current for specific interval of time.

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4 years ago
How do you calculate percentage uncertainties???
ch4aika [34]


I is just the uncertainty over the actual number multiplied by 100.


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36.1( +/- 0.1)

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3 years ago
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yawa3891 [41]

Answer:

6 Ω

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2 years ago
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