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stiv31 [10]
2 years ago
11

Do two bodies have to be in physical contact to exert a force upon one another?

Physics
1 answer:
Mekhanik [1.2K]2 years ago
3 0

The correct answer to the statement " Do two bodies have to be in physical contact to exert a force upon one another " is:

No, the gravitational force is a field force and does not require physical contact to exert

a force.

The correct option is a.

<h3>Why two bodies do not have to be in physical contact to exert a force upon one another as a result of gravitational force.</h3>

It has been practically proven that two bodies can exert a force upon each other even if there is no physical contact between them. This can as a result of gravity.

That being said, a magnetic attraction can also exert a force between two different bodies upon one another.

So therefore, it can be deduced from above that two different bodies do not have to be in physical contact before they exert a force upon one another.

Read more on force:

brainly.com/question/12970081

#SPJ1

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What is the proportionality constant between an object and<br> its acceleration by a given force?
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A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal fri
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Answer:

The speed of the knife after passing through the target is 9.33 m/s.

Explanation:

We can find the speed of the knife after the impact by conservation of linear momentum:

p_{i} = p_{f}

m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}}

Where:

m_{k}: is the mass of the knife = 22.5 g = 0.0225 kg

m_{t}: is the mass of the target = 300 g = 0.300 kg

v_{i_{k}}: is the initial speed of the knife = 40.0 m/s

v_{i_{t}}: is the initial speed of the target = 2.30 m/s

v_{f_{k}}: is the final speed of the knife =?

v_{f_{t}}: is the final speed of the target = 0 (it is stopped)

Taking as a positive direction the direction of the knife movement, we have:

m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}}  

v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s

Therefore, the speed of the knife after passing through the target is 9.33 m/s.

I hope it helps you!              

4 0
3 years ago
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