1.) The force of gravity is what we call weight, we define it as:
w=mg
w=5,7kg*9,8m/s²
w=55,86kg (b)
2.) We know that:
power=W/t
power=50J/20s
power=2,5Watts (a)
3.) The work done is equal to the potential energy, so:
Epg=mgh
Epg=63kg*9,8m/s²*7m
Epg=4321J
Now we get the power:
power=W/t
power=4321J/5s
power=864Watts
Now:
1HP=746Watts
=1,16HP (b)
4.) We know that:
F=ma
350N=m*10m/s²
m=350N/10m/s²
m=35kg (b)
5.) d.) Aceleration is tha rate of change in velocity, either positive (increasing) or negative (decreasing)
Answer: The size of the force varies inversely as the distance square between the two charges. Thus, if the distance between the two charges is doubled, the attraction or repulsion will become weaker and decrease to one-fourth of the original value. The size of the force shall be proportional to the value of each charge.
Explanation:
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A. movement of earths tectonic plates. I'm pretty sure
Answer:
Explanation:
Given
Initial velocity of first billiard ball ![u_1=3.4\ m/s](https://tex.z-dn.net/?f=u_1%3D3.4%5C%20m%2Fs)
Initial velocity of second billiard ball ![u_2=0\ m/s](https://tex.z-dn.net/?f=u_2%3D0%5C%20m%2Fs)
After collision first ball comes to rest
suppose m is the mass of both the balls
Conserving momentum to get the speed of second ball after collision
Initial momentum ![P_i=mu_1+mu_2=m\cdot 3.4+0](https://tex.z-dn.net/?f=P_i%3Dmu_1%2Bmu_2%3Dm%5Ccdot%203.4%2B0)
Final momentum ![P_f=mv_1+mv_2](https://tex.z-dn.net/?f=P_f%3Dmv_1%2Bmv_2)
where
and
are the speed of first and second ball respectively
![P_i=P_f](https://tex.z-dn.net/?f=P_i%3DP_f)
![m\cdot 3.4+0=0+m\cdot v_2](https://tex.z-dn.net/?f=m%5Ccdot%203.4%2B0%3D0%2Bm%5Ccdot%20v_2)
![v_2=3.4\ m/s](https://tex.z-dn.net/?f=v_2%3D3.4%5C%20m%2Fs)
thus speed of second ball after collision is equal to speed of first ball before collision
Answer:
A , power
Explanation:
Hope this is useful. Have a lovely rest of your day! God bless you.