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Amanda [17]
3 years ago
13

Boston Red Sox pitcher Roger Clemens could routinely throw a fastball at a horizontal

Physics
1 answer:
azamat3 years ago
6 0

Answer: 0.145 seconds

Explanation:

Given that Roger Clemens could routinely throw a fastball at a horizontal speed of 119.7 m/s. How long did the ball take to reach home plate 17.3 m away

Since the speed is horizontal

Using the formula for speed which is

Speed = distance/time

Where

Speed = 119.7 m/s

Distance covered = 17.3 m

Time is what we are looking for

Substitute all the parameters into the formula

119.7 = 17.3/ time

Make time the subject of formula

Time = 17.3 / 119.7

Time = 0.145 seconds.

Therefore, it will take 0.145 seconds to reach the home plates

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The answer would be A.
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Which process is represented by the PV diagram shown below?
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Answer: B. the isovolumetric process

Explanation:

In the graph given, the volume is constant throughout. It represents a constant volume process. Such processes are called the isovolumetric process or isochoric process.

<em>Hence, option B is the correct answer.</em>

Option A is incorrect because in an isobaric process, the pressure is constant.

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Option D is incorrect because in an adiabatic process there is no heat transfer.

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Answer:

no, not all three contains iron

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What type of objects cannot pull to magmets
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7 0
3 years ago
Read 2 more answers
A jet aircraft is traveling at 260 m/s in horizontal flight. The engine takes in air at a rate of 53.3 kg/s and burns fuel at a
IrinaVladis [17]

Answer:

The thrust of the jet engine is 4188.81 N.

Explanation:

Given that,

Speed = 260 m/s

Rate in air= 53.3 kg/s

Rate of fuel = 3.63 kg/s

Relative speed = 317 m/s

We need to calculate the rate of mass change in the rocket

Using formula of rate of mass

\dfrac{dM}{dt}=\dfrac{dM_{a}}{dt}+\dfrac{dM_{f}}{dt}

Put the value into the formula

\dfrac{dM}{dt}=53.3+3.63

\dfrac{dM}{dt}=56.93\ kg/s

We need to calculate the thrust of the jet engine

Using formula of thrust

T=\dfrac{dM}{dt}u-\dfrac{dM_{a}}{dt}v

Put the value into the formula

T=56.93\times317-53.3\times260

T=4188.81\ N

Hence, The thrust of the jet engine is 4188.81 N.

7 0
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