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statuscvo [17]
2 years ago
11

An object moving with 108 km/h moves 400 m in 8 seconds. find the velocity attained by the object.

Physics
1 answer:
wlad13 [49]2 years ago
3 0

Answer:50ms-1

Explanation:use the formula v=d/t

in order to find the velocity,devide the distance with time taken.

since distance is 400 meters devide it with seconds whiuch gives us 50.

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4 years ago
A sled with a mass of 32 kg is being pulled across the snow. If the friction force between the sled and the ground is 12 N, what
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Answer:

Fa= 47.2N

Explanation:

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Describe the conditions necessary for sublimation to occur.
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4 years ago
Read 2 more answers
While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the
Verdich [7]

The magnitude of the force is 18.6 N

Explanation:

The work done by a force on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the block in this problem, we have

W=-17.8 J is the work done

d = 1.35 m is the displacement of the block

\theta=135^{\circ} is the angle between the force and the displacement

Solving for F, we find the magnitude of the force:

F=\frac{W}{d cos \theta}=\frac{-17.8}{(1.35)(cos 135)}=18.6 N

Learn more about work here:

brainly.com/question/6763771

brainly.com/question/6443626

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8 0
4 years ago
A ball is dropped from a height of 20m and renounce with the velocity which is 3/4 of d velocity with which it hits the ground.
Mashutka [201]

Answer:

1.73 seconds

Explanation:

The velocity the ball first hits the ground with is:

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)

v = -20 m/s

The velocity it rebounds with is 3/4 of that in the opposite direction, or 15 m/s.

The time it takes to return to the ground is:

Δx = v₀ t + ½ at²

0 = (15 m/s) t + ½ (-10 m/s²) t²

0 = t (15 − 5t²)

t = √3

t ≈ 1.73 seconds

3 0
3 years ago
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